public String(String original) {
int size = original.count;
char[] originalValue = original.value;
char[] v;
if (originalValue.length > size) {
// The array representing the String is bigger than the new
// String itself. Perhaps this constructor is being called
// in order to trim the baggage, so make a copy of the array.
v = new char[size];
System.arraycopy(originalValue, original.offset, v, 0, size);
} else {
// The array representing the String is the same
// size as the String, so no point in making a copy.
v = originalValue;
}
this.offset = 0;
this.count = size;
this.value = v;
}
标记出的if语句什么时候会得到执行，我怎么觉得它不可能执行呢！
int size = original.count;
char[] originalValue = original.value;
char[] v;
if (originalValue.length > size) {
// The array representing the String is bigger than the new
// String itself. Perhaps this constructor is being called
// in order to trim the baggage, so make a copy of the array.
v = new char[size];
System.arraycopy(originalValue, original.offset, v, 0, size);
} else {
// The array representing the String is the same
// size as the String, so no point in making a copy.
v = originalValue;
}
this.offset = 0;
this.count = size;
this.value = v;
}
标记出的if语句什么时候会得到执行，我怎么觉得它不可能执行呢！
解决方案 »
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字符串的长度用length().
数组的长度用length.
length是长度
size是大小
int size = original.count; 其中count是什莫呢？求original的长度话，应该写成
int size = original.length();
new String("123");
if (originalValue.length > size)
难道就会执行？
size是0？
看这个帖子吧