JTree 删除节点 无法刷新

Question

DefaultMutableTreeNode node = (DefaultMutableTreeNode)path.getLastPathComponent();
DefaultTreeModel model = (DefaultTreeModel)tree.getModel();
model.removeNodeFromParent(node);被删除的节点还显示在tree中，遍历它的parent，已经没有了，咋办呢？？？？

Answer 1

DefaultMutableTreeNode node =(DefaultMutableTreeNode)path.getLastPathComponent();DefaultTreeModel model = (DefaultTreeModel)tree.getModel();DefaultMutableTreeNode parent = (DefaultMutableTreeNode)node.getParent();
model.removeNodeFromParent(node);
node.removeFromParent();
int count = model.getChildCount(parent);
System.out.println("parent: " + parent.getUserObject());Enumeration en = parent.children();
while(en.hasMoreElements()) {
     DefaultMutableTreeNode child = (DefaultMutableTreeNode)en.nextElement();
                System.out.println(child.getUserObject());
}

Answer 2

我是在jtree 的 drag & drop 实现里遇到该问题的。 后来发现，如果用注释中的语句就能成功删除，用以下第一行的语句得到TreePath就有问题。 不知道为什么。TreePath path = (TreePath)t.getTransferData(this.flavor);//TreePath path = (TreePath)tree.getSelectionPath();=================== 完整代码如下==================
public synchronized void drop(DropTargetDropEvent dtde) {
        // TODO Auto-generated method stub
        if(!this.isDropAcceptable(dtde)) {
            dtde.rejectDrop();
            return;
        }
        
        try {
            dtde.acceptDrop(dtde.getDropAction());
            
            DropTargetContext dtc = dtde.getDropTargetContext();
            JTree tree = (JTree)dtc.getComponent();
            
            Point pt = dtde.getLocation();
            TreePath newPath = tree.getClosestPathForLocation(pt.x, pt.y);
            DefaultMutableTreeNode newParent = (DefaultMutableTreeNode)newPath.getLastPathComponent();
            System.out.println(newParent.getUserObject());
            if(newParent.isLeaf()) {
                dtde.rejectDrop();
                return;
            }
            
            Transferable t = dtde.getTransferable();
            TreePath path = (TreePath)t.getTransferData(this.flavor);
            //TreePath path = (TreePath)tree.getSelectionPath();
            
            
            DefaultMutableTreeNode node = (DefaultMutableTreeNode)path.getLastPathComponent();
            
            //model.insertNodeInto(newNode, newParent, 0);
            DefaultMutableTreeNode parent = (DefaultMutableTreeNode)node.getParent();
            System.out.println("node: " + node.getUserObject());
            System.out.println("parent: " + parent.getUserObject());
            model.removeNodeFromParent(node);
        } catch (Exception e) {
            // TODO Auto-generated catch block
            System.out.println(e);
        }
        dtde.dropComplete(true);
        return;
    }

Answer 3

DefaultMutableTreeNode node = (DefaultMutableTreeNode)path.getLastPathComponent(); 
DefaultTreeModel model = (DefaultTreeModel)tree.getModel(); 
model.removeNodeFromParent(node);
model.nodeChanged(TreeNode node)

Answer 4

DefaultMutableTreeNode node = (DefaultMutableTreeNode)path.getLastPathComponent(); 如果用DefaultTreeModel方法构造的树，当树节点增加、删除时候不需要刷新树增加：model.insertNodeInto(MutableTreeNode newChild, MutableTreeNode parent, int index)
删除：model.removeNodeFromParent(node); 

Answer 5

sorry，写错了，我是这样实现的，你试一下，看看行不DefaultMutableTreeNode node = (DefaultMutableTreeNode path.getLastSelectedPathComponent(); 如果用DefaultTreeModel方法构造的树，当树节点增加、删除时候不需要刷新树 增加：model.insertNodeInto(MutableTreeNode newChild, MutableTreeNode parent, int index) 
删除：model.removeNodeFromParent(node); 

Answer 6

repaint();
//最好不要用upadateUI用insertNodeInto和removeNodeFromParent不需要刷新。