求段简单的Socket的代码

Question

编写一个自己给自己发消息，然后接收的代码
我就是接收不到，不知怎么的
谢谢

Answer 1

public class Test {
public static void main(String[] args) {
String text = "java project" ;
try {
Receive rev = new Receive() ;
rev.start() ;
InetAddress target = InetAddress.getByName("255.255.255.255");
byte[] buf = text.getBytes() ;
DatagramPacket sendPacket = new DatagramPacket(buf, buf.length, target, 6188) ;
DatagramSocket sendSocket = new DatagramSocket() ;
sendSocket.send(sendPacket) ;
sendSocket.close() ;
rev.interrupt() ;
} catch (Exception e) {
e.printStackTrace();
}

}public class Receive extends Thread {

public void run(){
while(true){
try {
byte[] array = new byte[1000];
DatagramPacket receivePacket = new DatagramPacket(array, array.length);
DatagramSocket receiveSocket = new DatagramSocket(6188);
receiveSocket.receive(receivePacket); String data = byteToString(receivePacket.getData(), receivePacket.getLength());
System.out.println(data);
} catch (Exception e) {
e.printStackTrace();
}
}
}


static String byteToString(byte[] yb, int len) {
String rs = "";
int i = 0;
char c;
for (i = 0; i < len; i++) {
c = (char) yb[i];
rs = rs + String.valueOf(c);
}
return (rs);
}}
请问我这有什么问题？

Answer 2

    public void run(){
          try {
               DatagramSocket receiveSocket = new DatagramSocket(6188);
              while(true){
          
                byte[] array = new byte[1000];
                DatagramPacket receivePacket = new DatagramPacket(array, array.length);
               
                receiveSocket.receive(receivePacket);                String data = byteToString(receivePacket.getData(), receivePacket.getLength());
                System.out.println(data);
         
        }
               } catch (Exception e) {
                e.printStackTrace();
            }
    }
调式成功~~~

Answer 3

DatagramSocket receiveSocket = new DatagramSocket(6188); 不能放在循环里面
给分~~~谢谢想贴调试结果的图片出来，好像没地方上传