Java初始化作业,做不通 圆有半径,并提供计算面积的方法,类里有属性圆数组,设计三个方法,分别获取数组中最大面积的圆、最小面积的圆、所有圆的面积和。 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 类里有属性圆数组:保存圆的半径数组中最大面积的圆:最大半径最小面积的圆:最小半径所有圆的面积和:PI(r1*r1+r2*r2....) 这个非常简单,一个 for套嵌if即可搞定 好吧,看在300分的面子上package test;public class Circle implements Comparable<Circle> { private double radius; public Circle(double radius) { this.radius = radius; } public double getArea() { return Math.PI * radius * radius; } public int compareTo(Circle circle4Compare) { return this.radius == circle4Compare.radius ? 0 : this.radius > circle4Compare.radius ? 1 : -1; }}package test;import java.util.*;public class CircleData { private List<Circle> circleList = new ArrayList<Circle>(); public void addCircle(Circle circle){ circleList.add(circle); Collections.sort(circleList); } public Circle getMaxCircle(){ if(circleList.size() > 0){ return circleList.get(circleList.size() -1); }else{ return null; } } public Circle getMinCircle(){ if(circleList.size() > 0){ return circleList.get(0); }else{ return null; } } public double getSumCircle(){ double sumArea = 0.0; for(Circle circle:circleList){ sumArea += circle.getArea(); } return sumArea; } public static void main(String[] args){ CircleData circleData = new CircleData(); circleData.addCircle(new Circle(2)); circleData.addCircle(new Circle(1)); circleData.addCircle(new Circle(4)); circleData.addCircle(new Circle(3)); System.out.println(circleData.getMinCircle().getArea()); System.out.println(circleData.getMaxCircle().getArea()); System.out.println(circleData.getSumCircle()); }} package csdn.p1;import java.util.ArrayList;import java.util.Collections;import java.util.List;/** * 圆有半径,并提供计算面积的方法,类里有属性圆数组, * 设计三个方法,分别获取数组中最大面积的圆、最小面积的圆、所有圆的面积和。 * @author zty * */public class Test { private List<Circle> circles; public Test() { this.circles = new ArrayList<Circle>(); } public Circle getMaxCircle() { Collections.sort(circles); return circles.get(circles.size()-1); } public Circle getMinCircle() { Collections.sort(circles); return circles.get(0); } public double getAllArea() { double areas = 0; for (Circle circle : circles) { areas = areas + circle.Area(); } return areas; } public static void main(String[] args) { Test ts = new Test(); ts.circles.add(new Circle(1)); ts.circles.add(new Circle(2)); ts.circles.add(new Circle(3)); ts.circles.add(new Circle(4)); ts.circles.add(new Circle(5)); System.out.println("最大圆:"+ts.getMaxCircle().toString()); System.out.println("最小圆:"+ts.getMinCircle().toString()); System.out.println("面积和"+ts.getAllArea()); }}class Circle implements Comparable<Circle>{ private double radius; public Circle(double radius) { this.radius = radius; } public double Area() { return Math.PI*radius*radius; } @Override public int compareTo(Circle c) { return this.radius >=c.radius? (this.radius>c.radius?1:0) :-1; } @Override public String toString() { return "Circle [半径=" + radius + "]"; }} 轻松一下,玩个小游戏,我实在想不出来结果 新手提问,JAVA的一个函数调用绑定问题。 JAVA软件怎么发布??? 大家谁有孙卫琴的《精通Struts》的电子版? 小应用程序问题 有疑惑 如何判断字符串是不是关键字 一个简单的程序,书上的,有问题. 那里有关于jmf的开发资料和介绍,请那位仁兄帮忙(最好介绍一些好的资料)急!! 一个java的入门问题 萌新求教,查询获取不到数据 Java 枚举类运用 随机产生字符串
数组中最大面积的圆:最大半径
最小面积的圆:最小半径
所有圆的面积和:PI(r1*r1+r2*r2....)
this.radius = radius;
} public double getArea() {
return Math.PI * radius * radius;
} public int compareTo(Circle circle4Compare) {
return this.radius == circle4Compare.radius ? 0
: this.radius > circle4Compare.radius ? 1
: -1;
}
}
package test;import java.util.*;public class CircleData { private List<Circle> circleList = new ArrayList<Circle>();
public void addCircle(Circle circle){
circleList.add(circle);
Collections.sort(circleList);
}
public Circle getMaxCircle(){
if(circleList.size() > 0){
return circleList.get(circleList.size() -1);
}else{
return null;
}
}
public Circle getMinCircle(){
if(circleList.size() > 0){
return circleList.get(0);
}else{
return null;
}
}
public double getSumCircle(){
double sumArea = 0.0;
for(Circle circle:circleList){
sumArea += circle.getArea();
}
return sumArea;
}
public static void main(String[] args){
CircleData circleData = new CircleData();
circleData.addCircle(new Circle(2));
circleData.addCircle(new Circle(1));
circleData.addCircle(new Circle(4));
circleData.addCircle(new Circle(3));
System.out.println(circleData.getMinCircle().getArea());
System.out.println(circleData.getMaxCircle().getArea());
System.out.println(circleData.getSumCircle());
}
}
import java.util.Collections;
import java.util.List;/**
* 圆有半径,并提供计算面积的方法,类里有属性圆数组,
* 设计三个方法,分别获取数组中最大面积的圆、最小面积的圆、所有圆的面积和。
* @author zty
*
*/
public class Test {
private List<Circle> circles;
public Test() {
this.circles = new ArrayList<Circle>();
}
public Circle getMaxCircle() {
Collections.sort(circles);
return circles.get(circles.size()-1);
}
public Circle getMinCircle() {
Collections.sort(circles);
return circles.get(0);
}
public double getAllArea() {
double areas = 0;
for (Circle circle : circles) {
areas = areas + circle.Area();
}
return areas;
}
public static void main(String[] args) {
Test ts = new Test();
ts.circles.add(new Circle(1));
ts.circles.add(new Circle(2));
ts.circles.add(new Circle(3));
ts.circles.add(new Circle(4));
ts.circles.add(new Circle(5));
System.out.println("最大圆:"+ts.getMaxCircle().toString());
System.out.println("最小圆:"+ts.getMinCircle().toString());
System.out.println("面积和"+ts.getAllArea());
}
}
class Circle implements Comparable<Circle>{
private double radius;
public Circle(double radius) {
this.radius = radius;
}
public double Area() {
return Math.PI*radius*radius;
}
@Override
public int compareTo(Circle c) {
return this.radius >=c.radius?
(this.radius>c.radius?1:0)
:-1;
}
@Override
public String toString() {
return "Circle [半径=" + radius + "]";
}
}