在JAVA中如何判断全角英数字和半角英数字

Question

比如JSP业面上有个文本框,我想在后台得到这个值,然后判断这个值,如果是全角英数字或者是半角英数字的话,就合法.
该如何实现,哪为朋友帮帮忙,谢了!

Answer 1

  <script language="javascript">
var regex = /[\uFF10-\uFF19]|[0-9]/g;
var s = "１２３４５６７８９25０1６23７54";
if(regex.test(s)){
alert(s+"\n"+strReplace(s));
}
function strReplace(val){
var arr = ["\uFF10","\uFF11","\uFF12","\uFF13","\uFF14","\uFF15","\uFF16","\uFF17","\uFF18","\uFF19"]; for(var i=0;i<arr.length;i++){
var reg = new RegExp(arr[i],"g")
val = val.replace(reg,i+"");
}
return val;
}
  </script>

Answer 2

  
<script language="javascript"> 
var regex = /[0-9\uFF10-\uFF19]/g; 
var s = "１２３４５６７８９25０1６23７54"; 
if(regex.test(s)){ 
   alert(s+"\n"+strReplace(s)); 
} 
function strReplace(val){ 
var arr = ["\uFF10","\uFF11","\uFF12","\uFF13","\uFF14","\uFF15","\uFF16","\uFF17","\uFF18","\uFF19"]; for(var i=0;i <arr.length;i++){ 
   var reg = new RegExp(arr[i],"g"); 
   val = val.replace(reg,i+""); 
} 
return val; 
} 
  </script>

Answer 3

<script language="javascript"> 
var regex = [0-9\uFF10-\uFF19]/g; 
var s = "１２３４５６７８９25０1６23７54"; 
if(regex.test(s)){ 
   alert(s+"\n"+strReplace(s)); 
} 
function strReplace(val){ 
var arr = ["\uFF10","\uFF11","\uFF12","\uFF13","\uFF14","\uFF15","\uFF16","\uFF17","\uFF18","\uFF19"]; for(var i=0;i <arr.length;i++){ 
   var reg = new RegExp(arr[i],"g"); 
   val = val.replace(reg,i+""); 
} 
return val; 
} 
  </script>第一次发贴，编辑器都不会用，老发错

Answer 4

这个用正则就可以搞定了，好像是说\uxxxx - \uxxxx 就是非ascii区域，不过我忘了 :)