关于延时repatint()的问题

Question

是这样的，我现在要做一个程序，每次计算完路径之后都要repaint()一次，以便显示这次走的格子和路径，总共40个回合，就要显示40次，但是现在我用Thread.sleep()，程序锁死，用timer的话，直接repaint最后一步，之前的显示不出来，我设的延时参数都是500ms.下面是我按完start按钮之后计算的执行的部分……
DPanel.update()是repaint（）命令……
 private class StartAction extends Thread implements ActionListener 
    {
        run r;
        ChasingCatStrDog Strd;
        
        
        public void actionPerformed(ActionEvent event) 
        {
            eat = 0;
            count = 0;
            ex = 0;
            java.util.Timer timer = new java.util.Timer();
            
            timer.schedule(new TimerTask()
            {
               public void run()
               {
       label1:     while(count < turn && eat == 0  && ex == 0)
                   {
                        r = new run(Str, c, d, grid);
                        Strd = new ChasingCatStrDog(c, d);
                        System.out.println("turn " + count +" "+ c.catx +" "+ c.caty);
                        DPanel.update();
                        if (c.catx == gate && c.caty == 0)
                        {
                            JDialog exDialog = new exitDialog(UIFrame.this);
                            exDialog.setVisible(true);
                            ex = 1;
                            break label1;
                        }
                        
                        count++;
                        for(int i = 0; i < dn; i++)
                        {
                            if((c.catx == d[i].dogx) && (c.caty == d[i].dogy))
                            {
                                JDialog eDialog = new eatDialog(UIFrame.this);
                                eDialog.setVisible(true);
                                eat = 1;
                                break label1;
                            }
                        }
                   }
               }             },500,500);
                 
                 
                 
                
            
            
        }
    }

Answer 1

此回复为自动发出,仅用于显示而已，并无任何其他特殊作用
楼主【jeffsyr】截止到2008-07-24 12:07:22的历史汇总数据(不包括此帖)：
发帖的总数量:1                        发帖的总分数:0                        每贴平均分数:0                        
回帖的总数量:0                        得分贴总数量:0                        回帖的得分率:0%                       
结贴的总数量:0                        结贴的总分数:0                        
无满意结贴数:0                        无满意结贴分:0                        
未结的帖子数:1                        未结的总分数:0                        
结贴的百分比:0.00  %               结分的百分比:---------------------
无满意结贴率:---------------------无满意结分率:---------------------
如何结贴请参考这里：http://topic.csdn.net/u/20080501/09/ef7ba1b3-6466-49f6-9d92-36fe6d471dd1.html

Answer 2

启动一个新线程，让它的死循环每次先 YourFrame.repaint() 然后再 Thread.sleep() 一会儿。

Answer 3

http://i.cn.yahoo.com/pzy123cn/blog/p_17/

Answer 4

我这么写还是不行啊，帮忙看看哪里不对好么？
  private class StartAction extends Thread implements ActionListener 
    {
        run r;
        ChasingCatStrDog Strd;
        
        
        public void actionPerformed(ActionEvent event) 
        {
            eat = 0;
            count = 0;
            ex = 0;
            
            
           Thread t = new Thread();
           t.start();
       label1:     while(count < turn && eat == 0  && ex == 0)
                   {
                        try
                        {
                            r = new run(Str, c, d, grid);
                        
                        Strd = new ChasingCatStrDog(c, d);
                        System.out.println("turn " + count +" "+ c.catx +" "+ c.caty);
                        DPanel.update();
                        t.sleep(speedvalue); 
                        if (c.catx == gate && c.caty == 0)
                        {
                            JDialog exDialog = new exitDialog(UIFrame.this);
                            exDialog.setVisible(true);
                            ex = 1;
                            break label1;
                        }
                        
                        count++;
                        for(int i = 0; i < dn; i++)
                        {
                            if((c.catx == d[i].dogx) && (c.caty == d[i].dogy))
                            {
                                JDialog eDialog = new eatDialog(UIFrame.this);
                                eDialog.setVisible(true);
                                eat = 1;
                                break label1;
                            }
                        }
                        }
                        catch(InterruptedException e)
                        {
                            
                        }
                   }
               }        }
    }

Answer 5

我按上面那么写还是最后一次才repaint()，之前的都没有显示啊555