这个线程式同步的程序,怎样把他改OK呢?谢谢!!!!(能处理一下死锁更好)

Question

public class SyncThread { StringBuffer sb1 = new StringBuffer();
StringBuffer sb2 = new StringBuffer();

public static void main(String[] args)
{
new Thread(synchronized(){
sb1.append('a');
System.out.println(sb1);
synchronized(){
sb2.append('d');
System.out.println(sb2);
}

}).start();
new Thread(synchronized run(){
sb2.append('b');
System.out.println(sb2);
synchronized(){
sb1.append('c');
System.out.println(sb1);
}

}).start();
}
}

Answer 1

此回复为自动发出,仅用于显示而已，并无任何其他特殊作用
楼主【hellosun2000】截止到2008-07-10 09:09:22的历史汇总数据(不包括此帖)：
发帖的总数量:10                       发帖的总分数:240                      每贴平均分数:24                       
回帖的总数量:9                        得分贴总数量:1                        回帖的得分率:11%                      
结贴的总数量:9                        结贴的总分数:230                      
无满意结贴数:1                        无满意结贴分:20                       
未结的帖子数:1                        未结的总分数:10                       
结贴的百分比:90.00 %               结分的百分比:95.83 %                  
无满意结贴率:11.11 %               无满意结分率:8.70  %                  
值得尊敬

Answer 2

建议楼主重写
你写的乱七八糟的
-------------------------------------------------------------
            Quietly through  .....

Answer 3

public class SyncThread {
    static StringBuffer sb1 = new StringBuffer();    static StringBuffer sb2 = new StringBuffer();    public static void main(String[] args) {
        new Thread() {
            public void run() {
                synchronized (sb1) {
                    sb1.append('a');
                    System.out.println(sb1);
                }
                synchronized (sb2) {
                    sb2.append('d');
                    System.out.println(sb2);
                }            }
        }.start();
        new Thread() {
            public void run() {
                synchronized (sb2) {
                    sb2.append('b');
                    System.out.println(sb2);
                }
                synchronized (sb1) {
                    sb1.append('c');
                    System.out.println(sb1);
                }            }
        }.start();
    }}

Answer 4

public class SyncThread { public static void main(String[] args) {
final StringBuilder sb1 = new StringBuilder();
final StringBuilder sb2 = new StringBuilder();
new Thread(
new Runnable() {
public void run() {
sb1.append('a');
System.out.println(sb1);
synchronized (sb2) {
sb2.append('d');
System.out.println(sb2);
}
}
}
).start();
new Thread(
new Runnable() {
public void run() {
sb1.append('a');
System.out.println(sb1);
synchronized (sb2) {
sb2.append('d');
System.out.println(sb2);
}
}
}
).start();
}}你是这意思？