请帮我看看代码吧，请把每一步什么意思都注释一下谢谢

Question

 // 项目经费查询---余额信息查询
    public ActionForward searchofprojectye(ActionMapping actionMapping,ActionForm actionForm, HttpServletRequest request,HttpServletResponse servletResponse) 
    {
     String year = request.getParameter("year");
     String projectType = request.getParameter("projectType");
     String projectNo = request.getParameter("projectNo");
     String passwordofproject = request.getParameter("passwordofproject");
        
        Row[] count = ProjectService.searchcountofprojectye(year,projectType,projectNo,passwordofproject); 
        //如果项目有重复：
        if(count.length!=1)
        {
         String flag = "default";
         request.setAttribute("flag", flag);
         return actionMapping.findForward("default");
        }
        Row[] result = ProjectService.searchresultofprojectye(year,projectType,projectNo);
       // Row[] subjecttype = ProjectService.searchsubjecttype(year);        request.setAttribute("count", count);
request.setAttribute("result", result);
        return actionMapping.findForward("resultofprojectye");
    }

Answer 1

用struts做的:     public ActionForward searchofprojectye(ActionMapping actionMapping,ActionForm actionForm, HttpServletRequest request,HttpServletResponse servletResponse)//action主方法,不多做解释 
    { 
    /*接受4个参数:年,项目类型,项目号和项目密码*/    String year = request.getParameter("year"); 
    String projectType = request.getParameter("projectType"); 
    String projectNo = request.getParameter("projectNo"); 
    String passwordofproject = request.getParameter("passwordofproject"); 
    /*接受4个参数:年,项目类型,项目号和项目密码*/    
        Row[] count = ProjectService.searchcountofprojectye(year,projectType,projectNo,passwordofproject); 
        //如果项目有重复：这块...是调用ProjectService类的静态方法searchcountofprojectye,目的是什么就不清楚了
        if(count.length!=1) 
        { 
        String flag = "default";//定义标志位 
        request.setAttribute("flag", flag); //保存到request中,在下次请求时候以便接受到
        return actionMapping.findForward("default"); //页面跳转
        } 
        Row[] result = ProjectService.searchresultofprojectye(year,projectType,projectNo); 
      // Row[] subjecttype = ProjectService.searchsubjecttype(year); 
        //返回查询结果的页面,用actionMapping进行跳转,"default","resultofprojectye"是在struts-config.xml中配置的        request.setAttribute("count", count); 
        request.setAttribute("result", result); 
        return actionMapping.findForward("resultofprojectye"); 
    }

Answer 2

Row[] 数组，没有用过呀，我都是用list,hashlist呀，没有用过这样的格式的，对了，这是struts里的效果呀，看来还是用点问题呀，用myeclipse自动生成的，就是有很好的跳转机制呀，不用你那样声名，引用啦，浪费java内存呀，对于项目大的话，简单的编码，也是决定系统好坏的标准呀！