求一个提取小括号的正则表达式

Question

如题求一个能提取小括号中内容的正则表达式,小弟新手初学,搞了半天也没搞明白.例子:asdfkjasldjkf(alsjk)df;lasdfljkasdfl;jkasdl;kj(asdfljk)fasdkjhasdf;只要能把上面这句话  小括号中的英文字符  提取出来就行...
希望大家多多帮忙...

Answer 1

 好象有个字符串截取函数(substring())
你自己翻一下Java帮助文档看怎么个用法

Answer 2

\([^)]*\) 提出来的是(alsjk)  (asdfljk)  不是英文字符吧

Answer 3

Pattern p = Pattern.compile("\\(.*?\\)");
Matcher m = p.matcher("asdfkjasldjkf(alsjk)df;lasdfljkasdfl;jkasdl;kj(asdfljk)fasdkjhasdf; 
");
while(m.find()){
    System.out.println(m.group());
}

Answer 4

Pattern p = Pattern.compile("\\((.*?)\\)");
Matcher m = p.matcher("asdfkjasldjkf(alsjk)df;lasdfljkasdfl;jkasdl;kj(asdfljk)fasdkjhasdf; 
");
while(m.find()){
    System.out.println(m.group(1));
}

Answer 5

String si = "asdfkjasldjkf(alsjk)df;lasdfljkasdfl;jkasdl;kj(asdfljk)fasdkjhasdf";
Pattern sip = Pattern.compile("(?s)(?:.s*?)?\\((.*?)?\\)(.*?)?"); 
Matcher mp = sip.matcher(si);
while(mp.find()){
System.out.println(mp.group(1));
}

Answer 6

或者这样：String si = "asdfkjasldjkf(alsjk)df;lasdfljkasdfl;jkasdl;kj(asdfljk)fasdkjhasdf";
Pattern sip = Pattern.compile("\\(([^\\)]*)\\)"); 
Matcher mp = sip.matcher(si);
while(mp.find()){
System.out.println(mp.group(1));
}