如何打开文件??? 如何实现根据Folder,FileName这两个变量Strig Folder="d:/temp/out";String FileName="multiplication";打开Folder文件夹下的FileName文件? 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 你说的“打开”是什么意思? 读取吗?如果是读取就用File myFile = new File(Folder + File.seperator + FileName);FileInputStream fis = FileInputStream(myFile); ....FileInputStream fin = new FileInputStream("d:\\hello.txt");BufferedReader bf = new BufferedReader(new InputStreamReader(fin));.... FileInputStream fin = new FileInputStream("d:\\hello.txt");以字节流方式打开BufferedReader bf = new BufferedReader(new InputStreamReader(fin));以字符流方式打开 String folder = "d:/temp/out/"; String fileName = "multiplication"; //txtString type = ".txt";String path = folder + fileName + type;FileInputStream fis = new FileInputStream( path );InputStreamReader isr = new InputStreamReader( fis );BufferedReader bf = new BufferedReader( isr ); 大家看看为什么我这个画不出图形来的? 如何反编译*.class文件呀? 文件目录的传输问题?? 求教:有关InputStreamReader(arg1,arg2)中的arg2 小应用程序的问题? jdbc连接SQL SERVER数据库在IE中显示(socket方面的)出错,请求帮助! 关于文件通过HTTP上传时应用服务器内存开销过大的问题。 简单问题呀!来帮忙解决一下嘛! 请问CMP BEAN和BMP BEAN谁跟其他的BEAN的耦合更松散? 关于线程的中处理集合一些问题. 100分赏金来了 java的swing布局问题~~ 一个关于方法重写的问题
读取吗?如果是读取就用
File myFile = new File(Folder + File.seperator + FileName);
FileInputStream fis = FileInputStream(myFile);
....
FileInputStream fin = new FileInputStream("d:\\hello.txt");
BufferedReader bf = new BufferedReader(new InputStreamReader(fin));
....
以字节流方式打开
BufferedReader bf = new BufferedReader(new InputStreamReader(fin));
以字符流方式打开
String folder = "d:/temp/out/";
String fileName = "multiplication";
//txt
String type = ".txt";
String path = folder + fileName + type;
FileInputStream fis = new FileInputStream( path );
InputStreamReader isr = new InputStreamReader( fis );
BufferedReader bf = new BufferedReader( isr );