在命令行下输入像20 30 90 49 45这样的数据,又没有什么函数让这些数字初始化a阿?? System.out.println("input source data: "); Scanner in = new Scanner(System.in); int a = new int[10]; ...
没有直接方法吧,应该自己写代码赋值 for example String s = in.nextLine(); String[] v = s.split("\\s+"); for (int i=0; i<v.length; i++) { try { a[i] = Integer.parseInt(v[i]); } catch (Exception e) { e.printStackTrace(); a[i] = -1; } }
System.out.println("input source data: "); Scanner in = new Scanner(System.in); ArrayList<Integer> datatemp = new ArrayList<Integer>(20); while (in.hasNext()) { int i = in.nextInt(); datatemp.add(i); } Integer[] data = (Integer[])datatemp.toArray(new Integer[0]); sort(data);
System.out.println(data);但是输入数据后按回车怎么没有反应呢?
这段代码可以解决你问题 package penglh;import java.util.Scanner; public class Test { public static void main(String[] args){ int a[]=new int[10]; System.out.println( "input source data: "); Scanner t=new Scanner(System.in); for(int i=0;i<a.length;i++){ a[i]=t.nextInt(); } for(int i=0;i<a.length;i++){ System.out.println(a[i]); }
} }
class axxx { public static void main(String[] args){ } }然后在执行的时候 java axxx {"10","20","30","40","50"} 取到String args[] 然后如果是数字,,就用Integer.parseInt(args[i])去转换好了
for example
String s = in.nextLine();
String[] v = s.split("\\s+");
for (int i=0; i<v.length; i++) {
try {
a[i] = Integer.parseInt(v[i]);
} catch (Exception e) {
e.printStackTrace();
a[i] = -1;
}
}
Scanner in = new Scanner(System.in); ArrayList<Integer> datatemp = new ArrayList<Integer>(20);
while (in.hasNext()) {
int i = in.nextInt();
datatemp.add(i);
}
Integer[] data = (Integer[])datatemp.toArray(new Integer[0]);
sort(data);
System.out.println(data);但是输入数据后按回车怎么没有反应呢?
package penglh;import java.util.Scanner;
public class Test {
public static void main(String[] args){
int a[]=new int[10];
System.out.println( "input source data: ");
Scanner t=new Scanner(System.in);
for(int i=0;i<a.length;i++){
a[i]=t.nextInt();
}
for(int i=0;i<a.length;i++){
System.out.println(a[i]);
}
}
}
public static void main(String[] args){
}
}然后在执行的时候
java axxx {"10","20","30","40","50"}
取到String args[]
然后如果是数字,,就用Integer.parseInt(args[i])去转换好了