用户列表 id 用户名 年龄 操作 操作
c c 3 删除 修改
b b 2 删除 修改
a a 1 删除 修改 ----------------------------------------------------------------------------
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"% >
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd" >
<%@include file="DBconn.jsp" % >
<%
int id = Integer.parseInt(request.getParameter("id"));
//取得连接状态对象
Statement stmt = conn.createStatement();
String sql = "delete from userinfo where id="+id;
int n = stmt.executeUpdate(sql);
out.println(n);
conn.close();
% >
-------------------------------------------------------------------------
org.apache.jasper.JasperException: Exception in JSP: /doDelete.jsp:6 3: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd" >
4: <%@include file="DBconn.jsp" % >
5: <%
6: int id = Integer.parseInt(request.getParameter("id"));
7:
8:
9:
Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:506)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:395)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
root cause java.lang.NumberFormatException: For input string: "c"
java.lang.NumberFormatException.forInputString(Unknown Source)
java.lang.Integer.parseInt(Unknown Source)
java.lang.Integer.parseInt(Unknown Source)
org.apache.jsp.doDelete_jsp._jspService(doDelete_jsp.java:63)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:97)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:334)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
note The full stack trace of the root cause is available in the Apache Tomcat/5.5.20 logs.
请问各位大哥line6这句语句要怎么改才能让程序顺利运行啊...
c c 3 删除 修改
b b 2 删除 修改
a a 1 删除 修改 ----------------------------------------------------------------------------
<%@ page language="java" contentType="text/html; charset=UTF-8"
pageEncoding="UTF-8"% >
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd" >
<%@include file="DBconn.jsp" % >
<%
int id = Integer.parseInt(request.getParameter("id"));
//取得连接状态对象
Statement stmt = conn.createStatement();
String sql = "delete from userinfo where id="+id;
int n = stmt.executeUpdate(sql);
out.println(n);
conn.close();
% >
-------------------------------------------------------------------------
org.apache.jasper.JasperException: Exception in JSP: /doDelete.jsp:6 3: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd" >
4: <%@include file="DBconn.jsp" % >
5: <%
6: int id = Integer.parseInt(request.getParameter("id"));
7:
8:
9:
Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:506)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:395)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
root cause java.lang.NumberFormatException: For input string: "c"
java.lang.NumberFormatException.forInputString(Unknown Source)
java.lang.Integer.parseInt(Unknown Source)
java.lang.Integer.parseInt(Unknown Source)
org.apache.jsp.doDelete_jsp._jspService(doDelete_jsp.java:63)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:97)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:334)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:314)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:264)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
note The full stack trace of the root cause is available in the Apache Tomcat/5.5.20 logs.
请问各位大哥line6这句语句要怎么改才能让程序顺利运行啊...
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哈哈,应该就是这个问题,你看“java.lang.NumberFormatException: For input string: "c"
”
c c 3 删除 修改
b b 2 删除 修改
a a 1 删除 修改 你这个中的id是String类型的啊!int id = Integer.parseInt(request.getParameter( "id ")); 这里声明的id怎么变成int类型了,Integer.parseInt(request.getParameter( "id "));当然会出错了!String id = (String)request.getParameter("id");这样应该就行了吧!!