public class A { public staic void main(String args[]) { int temp = 10; for(int i=1;i<temp;i++) { for(int j=1;j<=i;j++) { System.out.print(j); } System.out.println();//换行 } } }
public class A { public void paint(int temp) { for(int i=1;i<temp;i++) { for(int j=1;j<=i;j++) { System.out.print(j); } System.out.println();//换行 } } public staic void main(String args[]) { new A().paint(10); new A().paint(20); } }
public static void main(String[] args) { StringBuilder sb = new StringBuilder(""); for(int i=1; i<=6; i++) { System.out.println(sb.append(i)); } }
String s = ""; for(int i=1; i<=6; i++) { s = s + i; System.out.println(s); }
{
public staic void main(String args[])
{
int temp = 10;
for(int i=1;i<temp;i++)
{
for(int j=1;j<=i;j++)
{
System.out.print(j);
}
System.out.println();//换行
}
}
}
{
public void paint(int temp)
{
for(int i=1;i<temp;i++)
{
for(int j=1;j<=i;j++)
{
System.out.print(j);
}
System.out.println();//换行
}
}
public staic void main(String args[])
{
new A().paint(10);
new A().paint(20);
}
}
StringBuilder sb = new StringBuilder("");
for(int i=1; i<=6; i++) {
System.out.println(sb.append(i));
}
}
for(int i=1; i<=6; i++) {
s = s + i;
System.out.println(s);
}
System.out.println("12");
System.out.println("123");
System.out.println("1234");
System.out.println("12345");
System.out.println("123456");
System.out.println("12");
System.out.println("123");
System.out.println("1234");
System.out.println("12345");
System.out.println("123456");============================================
此乃最简单之法
import java.io.*;public class Pich
{
public static void main(String ar[])
{
int i,j;
for(i=1;i<Integer.valueOf(ar[0]).intValue();i++)//决定了要输入到的数字,循环的次数
{for(j=1;j<i+1;j++)//小循环
System.out.print(j);
System.out.println();//换行
}
}
}
for(int i=1; i<=6; i++) {
s = s + i;
System.out.println(s);
}这个方法不错,我也想到了。呵呵~~~