本题是ACM中的1002的其中一部分,这部分就是将形如 310-GINO 中的字母转为数字,但是发现当主函数为
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String input = in.next();
System.out.println(ChangeString(input));
}此时和预想的结果一致,但是加个输入控制次数的N值,却发现根本没有调用到函数,第二个主函数如下:
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
for(int i = 0 ; i < n ; i++)
{
String input = in.next();
System.out.println(ChangeString(input));
}
}哪位大哥大姐帮小弟一下 ,小弟在这先谢谢各位了
整个测试源代码如下:
import java.util.*;
public class Acm1001 { /**
* @param args
*/
public static String ChangeString(String k) {
String decoded = "";
char []origin = k.toCharArray();
for (int i = 0; i < origin.length; i++) {
switch (origin[i]) {
case '-':
decoded += '-';
break;
case 'A': case 'B': case 'C': case '2':
decoded += '2';
break;
case 'D': case 'E': case 'F': case '3':
decoded += '3';
break;
case 'G': case 'H': case 'I': case '4':
decoded += '4';
break;
case 'J': case 'K': case 'L': case '5':
decoded += '5';
break;
case 'M': case 'N': case 'O': case '6':
decoded += '6';
break;
case 'P': case 'R': case 'S': case '7':
decoded += '7';
break;
case 'T': case 'U': case 'V': case '8':
decoded += '8';
break;
case 'W': case 'X': case 'Y': case '9':
decoded += '9';
break;
case '1': case '0':
decoded += origin[i];
break;
}
}
return decoded;
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
for(int i = 0 ; i < n ; i++)
{
String input = in.next();
System.out.println(ChangeString(input));
}
}}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
String input = in.next();
System.out.println(ChangeString(input));
}此时和预想的结果一致,但是加个输入控制次数的N值,却发现根本没有调用到函数,第二个主函数如下:
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
for(int i = 0 ; i < n ; i++)
{
String input = in.next();
System.out.println(ChangeString(input));
}
}哪位大哥大姐帮小弟一下 ,小弟在这先谢谢各位了
整个测试源代码如下:
import java.util.*;
public class Acm1001 { /**
* @param args
*/
public static String ChangeString(String k) {
String decoded = "";
char []origin = k.toCharArray();
for (int i = 0; i < origin.length; i++) {
switch (origin[i]) {
case '-':
decoded += '-';
break;
case 'A': case 'B': case 'C': case '2':
decoded += '2';
break;
case 'D': case 'E': case 'F': case '3':
decoded += '3';
break;
case 'G': case 'H': case 'I': case '4':
decoded += '4';
break;
case 'J': case 'K': case 'L': case '5':
decoded += '5';
break;
case 'M': case 'N': case 'O': case '6':
decoded += '6';
break;
case 'P': case 'R': case 'S': case '7':
decoded += '7';
break;
case 'T': case 'U': case 'V': case '8':
decoded += '8';
break;
case 'W': case 'X': case 'Y': case '9':
decoded += '9';
break;
case '1': case '0':
decoded += origin[i];
break;
}
}
return decoded;
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
for(int i = 0 ; i < n ; i++)
{
String input = in.next();
System.out.println(ChangeString(input));
}
}}
这句话是什么意思?程序执行后的输出结果是什么?