使用 Math.random()来实现百钱百鸡方法？

Question

我换了很多种方法
不管是嵌入FOR循环 还是 if语句
都要报错。
无法使用random 来实现百钱百鸡呢？高手麻烦写个来看看

Answer 1

/*百钱买百鸡
*公鸡五钱一只;母鸡三钱一只;小鸡一钱三只;
*
*现有一百钱,问可以买多少只公鸡,母鸡.小鸡?
*/
public class Baiqian
{
    public static void main(String [] args)
    {
        int x=0,z=0;
        int y;
        for(int i=0;i<20;i++){
         x=i;
           for(int j=3;j<100;j+=3){
            z=j;
            y=100-x-z;
            if(5*x+3*y+z/3==100&&y>0&&x>0){
            System.out.print(x+"\t"+y+"\t"+z+"\t");
            System.out.println();
          }
            }
    }
}
}
这是我最初写的代码。
直接给你贴出来了。

Answer 2

public class Chicken {
private static int chicken1 = 15;
private static int chicken2 = 9;
private static int chicken3 = 1;
private static int total = 300; /**
 * @param args
 */
public static void main(String[] args) {
for (int i = 0; i <= 20; i ++ ){
for (int j = 0; j <= 34; j ++ ){
for (int k = 0; k <= 300; k += 3){
if( i*chicken1 +j*chicken2+k*chicken3 == total){
System.out.println("(" + i + "," + j + "," + k + ")");
}
}
}
}
}}输出结果：
(0,0,300)
(0,1,291)
(0,2,282)
(0,3,273)
(0,4,264)
(0,5,255)
(0,6,246)
(0,7,237)
(0,8,228)
(0,9,219)
(0,10,210)
(0,11,201)
(0,12,192)
(0,13,183)
(0,14,174)
(0,15,165)
(0,16,156)
(0,17,147)
(0,18,138)
(0,19,129)
(0,20,120)
(0,21,111)
(0,22,102)
(0,23,93)
(0,24,84)
(0,25,75)
(0,26,66)
(0,27,57)
(0,28,48)
(0,29,39)
(0,30,30)
(0,31,21)
(0,32,12)
(0,33,3)
(1,0,285)
(1,1,276)
(1,2,267)
(1,3,258)
(1,4,249)
(1,5,240)
(1,6,231)
(1,7,222)
(1,8,213)
(1,9,204)
(1,10,195)
(1,11,186)
(1,12,177)
(1,13,168)
(1,14,159)
(1,15,150)
(1,16,141)
(1,17,132)
(1,18,123)
(1,19,114)
(1,20,105)
(1,21,96)
(1,22,87)
(1,23,78)
(1,24,69)
(1,25,60)
(1,26,51)
(1,27,42)
(1,28,33)
(1,29,24)
(1,30,15)
(1,31,6)
(2,0,270)
(2,1,261)
(2,2,252)
(2,3,243)
(2,4,234)
(2,5,225)
(2,6,216)
(2,7,207)
(2,8,198)
(2,9,189)
(2,10,180)
(2,11,171)
(2,12,162)
(2,13,153)
(2,14,144)
(2,15,135)
(2,16,126)
(2,17,117)
(2,18,108)
(2,19,99)
(2,20,90)
(2,21,81)
(2,22,72)
(2,23,63)
(2,24,54)
(2,25,45)
(2,26,36)
(2,27,27)
(2,28,18)
(2,29,9)
(2,30,0)
(3,0,255)
(3,1,246)
(3,2,237)
(3,3,228)
(3,4,219)
(3,5,210)
(3,6,201)
(3,7,192)
(3,8,183)
(3,9,174)
(3,10,165)
(3,11,156)
(3,12,147)
(3,13,138)
(3,14,129)
(3,15,120)
(3,16,111)
(3,17,102)
(3,18,93)
(3,19,84)
(3,20,75)
(3,21,66)
(3,22,57)
(3,23,48)
(3,24,39)
(3,25,30)
(3,26,21)
(3,27,12)
(3,28,3)
(4,0,240)
(4,1,231)
(4,2,222)
(4,3,213)
(4,4,204)
(4,5,195)
(4,6,186)
(4,7,177)
(4,8,168)
(4,9,159)
(4,10,150)
(4,11,141)
(4,12,132)
(4,13,123)
(4,14,114)
(4,15,105)
(4,16,96)
(4,17,87)
(4,18,78)
(4,19,69)
(4,20,60)
(4,21,51)
(4,22,42)
(4,23,33)
(4,24,24)
(4,25,15)
(4,26,6)
(5,0,225)
(5,1,216)
(5,2,207)
(5,3,198)
(5,4,189)
(5,5,180)
(5,6,171)
(5,7,162)
(5,8,153)
(5,9,144)
(5,10,135)
(5,11,126)
(5,12,117)
(5,13,108)
(5,14,99)
(5,15,90)
(5,16,81)
(5,17,72)
(5,18,63)
(5,19,54)
(5,20,45)
(5,21,36)
(5,22,27)
(5,23,18)
(5,24,9)
(5,25,0)
(6,0,210)
(6,1,201)
(6,2,192)
(6,3,183)
(6,4,174)
(6,5,165)
(6,6,156)
(6,7,147)
(6,8,138)
(6,9,129)
(6,10,120)
(6,11,111)
(6,12,102)
(6,13,93)
(6,14,84)
(6,15,75)
(6,16,66)
(6,17,57)
(6,18,48)
(6,19,39)
(6,20,30)
(6,21,21)
(6,22,12)
(6,23,3)
(7,0,195)
(7,1,186)
(7,2,177)
(7,3,168)
(7,4,159)
(7,5,150)
(7,6,141)
(7,7,132)
(7,8,123)
(7,9,114)
(7,10,105)
(7,11,96)
(7,12,87)
(7,13,78)
(7,14,69)
(7,15,60)
(7,16,51)
(7,17,42)
(7,18,33)
(7,19,24)
(7,20,15)
(7,21,6)
(8,0,180)
(8,1,171)
(8,2,162)
(8,3,153)
(8,4,144)
(8,5,135)
(8,6,126)
(8,7,117)
(8,8,108)
(8,9,99)
(8,10,90)
(8,11,81)
(8,12,72)
(8,13,63)
(8,14,54)
(8,15,45)
(8,16,36)
(8,17,27)
(8,18,18)
(8,19,9)
(8,20,0)
(9,0,165)
(9,1,156)
(9,2,147)
(9,3,138)
(9,4,129)
(9,5,120)
(9,6,111)
(9,7,102)
(9,8,93)
(9,9,84)
(9,10,75)
(9,11,66)
(9,12,57)
(9,13,48)
(9,14,39)
(9,15,30)
(9,16,21)
(9,17,12)
(9,18,3)
(10,0,150)
(10,1,141)
(10,2,132)
(10,3,123)
(10,4,114)
(10,5,105)
(10,6,96)
(10,7,87)
(10,8,78)
(10,9,69)
(10,10,60)
(10,11,51)
(10,12,42)
(10,13,33)
(10,14,24)
(10,15,15)
(10,16,6)
(11,0,135)
(11,1,126)
(11,2,117)
(11,3,108)
(11,4,99)
(11,5,90)
(11,6,81)
(11,7,72)
(11,8,63)
(11,9,54)
(11,10,45)
(11,11,36)
(11,12,27)
(11,13,18)
(11,14,9)
(11,15,0)
(12,0,120)
(12,1,111)
(12,2,102)
(12,3,93)
(12,4,84)
(12,5,75)
(12,6,66)
(12,7,57)
(12,8,48)
(12,9,39)
(12,10,30)
(12,11,21)
(12,12,12)
(12,13,3)
(13,0,105)
(13,1,96)
(13,2,87)
(13,3,78)
(13,4,69)
(13,5,60)
(13,6,51)
(13,7,42)
(13,8,33)
(13,9,24)
(13,10,15)
(13,11,6)
(14,0,90)
(14,1,81)
(14,2,72)
(14,3,63)
(14,4,54)
(14,5,45)
(14,6,36)
(14,7,27)
(14,8,18)
(14,9,9)
(14,10,0)
(15,0,75)
(15,1,66)
(15,2,57)
(15,3,48)
(15,4,39)
(15,5,30)
(15,6,21)
(15,7,12)
(15,8,3)
(16,0,60)
(16,1,51)
(16,2,42)
(16,3,33)
(16,4,24)
(16,5,15)
(16,6,6)
(17,0,45)
(17,1,36)
(17,2,27)
(17,3,18)
(17,4,9)
(17,5,0)
(18,0,30)
(18,1,21)
(18,2,12)
(18,3,3)
(19,0,15)
(19,1,6)
(20,0,0)

Answer 3

hehe，楼上解决的是“百钱买鸡”问题，不是“百钱百鸡”问题  ;)

Answer 4

你把其中的三个数之和=100的取出来不就是的了~~~if( i*chicken1 +j*chicken2+k*chicken3 == total && i+j+k == 100){
  System.out.println("(" + i + "," + j + "," + k + ")");
}(0,25,75)
(4,18,78)
(8,11,81)
(12,4,84)^_^

Answer 5

> 你把其中的三个数之和=100的取出来不就是的了~~~不错，hehe你这种是“后验”的方法。如果从算法优化的角度考虑，充分利用题目中的约束条件，用“先验”的方法，就可以减少一些运算次数了。

Answer 6

晕 我的意思诸位都没明白啊。。我想的是 用Math.random()进行生成随机数，将随机数转换成int类型,再用其算出百钱百鸡的方法。

Answer 7

我搞着玩的，主要是一时兴趣。
但发现random在一些取值方面用不起。
看看有没有解决方法。
public class baiqianbaiji2 {
public static void main(String[] arg) {
int  total = 100 ,
      gongji=5,
      muji=3,
      gj=0；
  
 
for(int mj=0;mj<=100;mj++) {
gj=(int)Math.random();
if( (total-mj*muji-gj*gongji)*3== total-mj-gongji  ) {


}
System.out.println(gj+";"+mj+";"+(total-mj-gongji));
  } 
  }
}