求教：怎么分割这个字符串呀 ？？？

Question

String ttt= "2004,1,2005,0,2006,3,2004,0,2005,0,2006,1,";
分割为
aaa[0]= "2004,1,2005,0,2006,3,";aaa[1]= "2004,0,2005,0,2006,1,";

Answer 1

String t = ttt.substring(0,ttt.length()/2);
String tt = ttt.substring(ttt.length()/2,ttt.length());

Answer 2

LZ 为社么不把用|分割呢?
String ttt= "2004,1,2005,0,2006,3|2004,0,2005,0,2006,1,";
Scanner scanner=new Scanner("\\|");
取值，毕竟没有规律的字串是很难分割的

Answer 3

二楼的好像不正确吧~！String ttt= "2004,1,2005,0,2006,33,2004,0,2005,0,2006,1,";
String tt = ttt.substring(0, ttt.length()/2+1);
String t = ttt.substring(ttt.length()/2+1, ttt.length());

Answer 4

String s = "2004,1,2005,0,2006,3,2004,0,2005,0,2006,1,";
Pattern p = Pattern.compile("([0-9]{4},[0-9]{1},[0-9]{4},[0-9]{1},[0-9]{4},)");
Matcher m = p.matcher(s);
while(m.find()){
System.out.println(m.group());
}

Answer 5

Pattern p = Pattern.compile("(\\d{4},\\d{1,},\\d{4},\\d{1,},\\d{4},\\d{1,})");
Matcher m = p.matcher(s);
while(m.find())
{
System.out.println(m.group());
}

Answer 6

import java.util.regex.*;
public class Test1
{
public static void main(String[] args)
{
String s = "2004,1,2005,0,2006,3,2004,0,2005,0,2006,1,";
s=s.replaceAll("3,","3.");
String[] strs=s.split("\\.");
System.out.println(strs[0]+",");
System.out.println(strs[1]);
}

}

Answer 7

正则当然是第一选择了。
Pattern p = Pattern.compile("(\\d{4},\\d{1,},\\d{4},\\d{1,},\\d{4},\\d{1,})");
Matcher m = p.matcher(s);
while(m.find())
{
System.out.println(m.group());
}
如果不熟悉，也可以用土方法。比如split成数组，然后6拼1
String arr[] = s.split(",");for(int i=0;i<arr.length/6;i++)
{
String combit = arr[6*i]+','+arr[6*i+1]+','+arr[6*i+2]+','+arr[6*i+3]+','+arr[6*i+4]+','+arr[6*i+5];
System.out.println(combit);
}
或者干脆用indexOf找6次int index = 0;
int temp = 0;
while(true)
{

for(int i=0;i<6;i++){
temp = s.indexOf(',',temp+1);
if(temp<0)
break;
}
if(temp<0)
break;
String sub = s.substring(index,temp);
index = temp+1;

System.out.println(sub);
}