Socket(客户端)建立代码:
try {
socket = new Socket(InetAddress.getByName("221.133.231.38"),554);
//socket = new Socket("221.133.231.38",554);
System.out.println(" 2");
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
--------------------------------------------------
socket = new Socket(InetAddress.getByName("221.133.231.38"),554);这句话引出的异常,可我以前都是这样写的!IP可以ping通,这是怎么回事?
rtsp://221.133.231.38:554/timeradio.rm这个地址也是好的!
这是为什么?这是为什么?
try {
socket = new Socket(InetAddress.getByName("221.133.231.38"),554);
//socket = new Socket("221.133.231.38",554);
System.out.println(" 2");
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
--------------------------------------------------
socket = new Socket(InetAddress.getByName("221.133.231.38"),554);这句话引出的异常,可我以前都是这样写的!IP可以ping通,这是怎么回事?
rtsp://221.133.231.38:554/timeradio.rm这个地址也是好的!
这是为什么?这是为什么?
直接写不就行了吗?
然后再跟踪下InetAddress.getByName("221.133.231.38")这是不是没取到值,这两句话应该是等价的
java.net.NoRouteToHostException: No route to host没有找到路由,换下端口
教科书上写着1-1024是系统保留端口~~用9819