import java.io.*;
public class aaa { public static void main(String[] args) {
BufferedReader in = new BufferedReader(
new InputStreamReader(System.in));
String[] arr = new String[3];
try{
for(int i = 0;i < arr.length;i++)
{
System.out.println("输入:");
String x = in.readLine();
arr[i] = x; System.out.println("是否继续?(Y/N)");
char c = (char)in.read(); if(c == 'Y')
{
continue;
}
else if(c == 'N')
{
break;
}
}
}
catch(IOException e){}
catch(NumberFormatException e){}
}
}
我想每次“输入”之后选择Y的时候都继续“输入”,第一次输入是正常的,可是选择Y之后第二次“输入”却不执行,直接询问是否继续,“String x = in.readLine();”这句在第二次输入的时候不起作用,这是为什么啊?
public class aaa { public static void main(String[] args) {
BufferedReader in = new BufferedReader(
new InputStreamReader(System.in));
String[] arr = new String[3];
try{
for(int i = 0;i < arr.length;i++)
{
System.out.println("输入:");
String x = in.readLine();
arr[i] = x; System.out.println("是否继续?(Y/N)");
char c = (char)in.read(); if(c == 'Y')
{
continue;
}
else if(c == 'N')
{
break;
}
}
}
catch(IOException e){}
catch(NumberFormatException e){}
}
}
我想每次“输入”之后选择Y的时候都继续“输入”,第一次输入是正常的,可是选择Y之后第二次“输入”却不执行,直接询问是否继续,“String x = in.readLine();”这句在第二次输入的时候不起作用,这是为什么啊?
public class aaa { public static void main(String[] args) { String[] arr = new String[3];
try{
for(int i = 0;i < arr.length;i++)
{ BufferedReader in = new BufferedReader(
new InputStreamReader(System.in));
System.out.println("输入:");
String x = in.readLine();
arr[i] = x; System.out.println("是否继续?(Y/N)");
char c = (char)in.read(); if(c == 'Y')
{
continue;
}
else if(c == 'N')
{
break;
}
}
}
catch(IOException e){}
catch(NumberFormatException e){}
}
}
要重新申请对象把
习惯是这样的拉 哇哈哈
最好还加句in.close();