获取xml值的问题，简单，知道的来拿分

Question

var xmlStr="<xml><row a1="kkkk" a2="lll" a3="2007-04-26 00:00:00" /></xml>"
var xmlDoc= new ActiveXObject('Microsoft.XMLDOM');
xmlDoc.async=false;
xmlDoc.loadXML(xmlStr);var a2=xmlDoc.getElementsByTagName('data')[0].childNodes[0].getAttribute('a2');

Answer 1

错了点点var a2=xmlDoc.getElementsByTagName('data')[0].childNodes[0].getAttribute('a2');
＝＝＝＝＞
var a2=xmlDoc.getElementsByTagName('row')[0].childNodes[0].getAttribute('a2');

Answer 2

错了点点var a2=xmlDoc.getElementsByTagName('data')[0].childNodes[0].getAttribute('a2');
＝＝＝＝＞
var a2=xmlDoc.getElementsByTagName('row')[0].getAttribute('a2');

Answer 3

xmlDoc.selectNodes()var doc = new ActiveXObject("MSXML2.DOMDocument.3.0");
var xmlStr="<xml><row a1='kkkk' a2='lll' a3='2007-04-26 00:00:00' /><row a1='kkkk' a2='bbbb' a3='2007-04-26 00:00:00' /></xml>";
doc.loadXML(xmlStr);
var nodes = doc.selectNodes("xml/row");//获取多行
for (var i = 0; i < nodes.length; i++)
{
    alert(nodes[i].getAttribute("a2"));
}

Answer 4

var a2=xmlDoc.getElementsByTagName('row')[0].getAttribute('a2');

Answer 5

xmlDoc.getElementsByTagName('row')[0].getAttribute('a2');