求 javascript 操作XML 的 代码?

和asp等类似，只是js区分大小写
http://msdn.microsoft.com/library/en-us/xmlsdk/html/e9da2722-7879-4e48-869c-7f16714e2824.asp
下有各种方法和例子

解决方案 »

  1.   

    http://msdn.microsoft.com/library/en-us/xmlsdk/html/79c78508-c9d0-423a-a00f-672e855de401.asp
      

  2.   

    北方博客 > 首页 > 用javascript读xml的例子 3上一篇: Tomcat 配置集锦  下一篇: 史上北方博客的几十次更新!4 
    [IT技术]用javascript读xml的例子 
    --------------------------------------------------------------------------------
    Tags: - 
    1.xml文件如下：<?xml version="1.0" encoding="UTF-8"?>
    <zip>
    <city>
    mycity</city>
    <state>mystate</state>
    </zip>2.读此xml的javascript例子：<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
    <title>Insert title here</title>
    <script language="javascript"  type="text/javascript">var url = "NewFile.xml"; 
    String.prototype.Trim = function() { return this.replace(/(^\s*)|(\s*$)/g, ""); }var xmlDoc; var moz = (typeof document.implementation != 'undefined') 
       && (typeof document.implementation.createDocument != 'undefined');
     var ie = (typeof window.ActiveXObject != 'undefined');function importXML(file) { if (moz) {
       xmlDoc = document.implementation.createDocument("", "doc", null); } else if (ie) {
       xmlDoc = new ActiveXObject("MSXML2.DOMDocument.3.0");
       xmlDoc.async = false;
       while(xmlDoc.readyState != 4) {};
     }
     
     xmlDoc.load(file);
    }
    importXML(url);function updateCityState(){
    if (moz) {
     var zip = xmlDoc.getElementsByTagName("zip")[0];
     var city;
        var _city = zip.getElementsByTagName("city")[0].firstChild.nodeValue;
          if (_city)   city = _city.Trim();
          
         var state;
         var _state=zip.getElementsByTagName("state")[0].firstChild.nodeValue;
         if(_state) state = _state.Trim();      document.getElementById('city').value = city;
          document.getElementById('state').value = state;
          
    } else if (ie) {
        var city;
        var _city = xmlDoc.selectSingleNode("/zip/city");
          if (_city) city = _city.text;
         var state;
         var _state=xmlDoc.selectSingleNode("/zip/state");
         if(_state) state = _state.text;
           document.getElementById('city').value = city;
          document.getElementById('state').value = state;  
      }    
    }
    </script>
    </head>
    <body>
    <form action="post">  <p>
      ZIP code:
      <input type="text" size="5" name="zip" id="zip" onblur="updateCityState();" />  </p>
      City:
      <input type="text" name="city" id="city" />  State:
      <input type="text" size="2" name="state" id="state" /></form>
    </body>
    </html> 
      

  3.   

    帮我看看,为什么这都会错?下面是XML文件:<?xml version="1.0" ?><!DOCTYPE xWinDoc [
    <!ELEMENT xWin (title, ID, msg, creator)>
    <!ELEMENT xWinList (xWin)*>
    <!ELEMENT title (#PCDATA)>
    <!ELEMENT ID (#PCDATA)>
    <!ELEMENT msg (#PCDATA)>
    <!ELEMENT creator (#PCDATA)>
    ]><xWinList>
    <xWin>
    <title>xWin</title>
    <ID>0</ID>
    <msg><![CDATA[
          TEST 1 
        ]]></msg>
    <creator>ADMIN</creator>
    </xWin><xWin>
    <title>xWin</title>
    <ID>1</ID>
    <msg><![CDATA[
           TEST 2
        ]]></msg>
    <creator>ADMIN</creator>
    </xWin>
    </xWinList>下面是HTML:
    HTML>
    <BODY>
    <SCRIPT LANGUAGE="JScript"> function fnCheck()
    {
       var xmldoc = new ActiveXObject("Msxml2.DOMDocument");
       xmldoc.async = false;   
       while( xmldoc.readyState != 4){}
       xmldoc.load("data.xml");
       if(xmldoc == null) alert("Load faild");
        var tNode = xmldoc.selectSingleNode("/xWinList/xWin");
          if (tNode) alert("find it!");}</SCRIPT>
    <INPUT TYPE=button VALUE="Test" onclick="fnCheck()"> 
    </SCRIPT>             
    </BODY>
    </HTML>点击button居然一点反映都没有. 是怎么回事?
      

  4.   

    bu zhi dao, tou da..