根据screen.width和screen.height判断

解决方案 »

  1.   

    if(screen.width==800){  
                              url   =   "../main/flash2.htm"  
      }else{  
                              url   =   "../main/flash.htm"  
      }
      

  2.   

    <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
    <HTML>
    <HEAD>
    <TITLE> New Document </TITLE>
    </HEAD><BODY>
    <script src='' id=s1></script>  <script language="JavaScript" type="text/javascript">
    if(screen.width>800){
    document.all['s1'].src = "2.js";
    }
    else{
    document.all['s1'].src = "1.js";
    }//alert(screen.width);
    </script></BODY>
    </HTML>