很奇怪的问题关于onmouseout & onmouseover

Question

onmouseover 是你鼠标在 alldiv上面才有效果嘛,出去当然就没了

Answer 1

你可以加一个参数
var a = 0;DIV1 onmouserout a = 1AllDIVAllDIV onmouserout if a = 1 then 你的离开事件 然后最好是把a还原成0

Answer 2

onmouseout => onmouseleave

Answer 3

对于ie，onmouseout在以下情况下触发：
event.fromElement!=event.toElement 并且 this.contains(event.fromElement)所以，“当鼠标移出 DIV1的时候，AllDIV 就触发了onmouseout事件”

Answer 4

<div id="aa" onmouseover="showdiv()" onmouseout="test(this.style);" style="position:absolute; left:175px; top:81px; width:219px; height:188px;background-color: #999999;">
<br>
<div id="hh" style="visibility:hidden;background-color: #CCCCCC;"">fdasfdas</div>
</div><script>
  function test(tag){
    var x=event.clientX;
    var y=event.clientY;
    var tleft=parseInt(tag.left)+1
    var ttop=parseInt(tag.top)+1
    var tright=parseInt(tag.left)+parseInt(tag.width)
    var tbottom=parseInt(tag.top)+parseInt(tag.height)
    if((tleft>=x&&tright>=x)||(tleft<=x&&tright<=x)||(ttop>=y&&tbottom>=y)||(ttop<=y&&tbottom<=y)){
        hh.style.visibility = "hidden";
    }else{
     hh.style.visibility = "";
    }
  }
 
   function showdiv(){
    hh.style.visibility = "";
  }
</script>