js字符串分割求教。

Question

118.532016,31.758281|118.522853,31.758066|118.515559,31.764329|118.8255715,31.8690843|118.515092,31.755855|118.532411,31.755763|用一个循环分割成如下，请问怎么分割呢？
 new BMap.Point(118.532016,31.758281);
 new BMap.Point(118.522853,31.758066);
 new BMap.Point(118.515559,31.764329);
 new BMap.Point(118.8255715,31.8690843);
 new BMap.Point(118.515092,31.755855);
 new BMap.Point(118.532411,31.755763);

Answer 1

<script type="text/javascript">
var s = '118.532016,31.758281|118.522853,31.758066|118.515559,31.764329|118.8255715,31.8690843|118.515092,31.755855|118.532411,31.755763|';
s = s.split('|');
for( var i = 0, len = s.length; i < len; i++ ){
if( s[i].length ){
document.write( 'new BMap.Point('+ s[i] +');' )
document.write( '<br>' )
}
}
</script>

Answer 2

这问题昨天不是提过吗？
var str = '118.532016,31.758281|118.522853,31.758066|118.515559,31.764329|118.8255715,31.8690843|118.515092,31.755855|118.532411,31.755763|';
str= str.split('|');
str.pop();/*弹出最后一个空的*/
var temp;
for(var i = 0  ; i < str.length ; ++i){
    temp = str[i].split(',');
     new BMap.Point(temp[0],temp[1]);
}