怎么根据两个日期得到除节假日周末外的天数

嗯写错了，原把转后天数拿来算星期出错了function workdays(d1,d2){
  function toD(d){return Date.parse(d)/864E5>>0}
  var day=new Date(d1).getDay(),d,
    d1=toD(d1),d2=toD(d2),works=0;
  if(d1>d2){d=d1;d1=d2;d2=d}
  while(d1<=d2) if( (day+d2-d1++)%7%6 ) works++;
  return works;
}

改了下，兼容低版本浏览器function workdays(d1,d2){
  function toD(d){return new Date(d.replace(/-/g,'/')) }
  function ds(d){return d.getTime()/864E5>>0}
  var day,d,d1=toD(d1),d2=toD(d2),works=0;
  if(d1>d2){d=d1;d1=d2;d2=d}
  day=d1.getDay();
  d1=ds(d1),d2=ds(d2);
  while(d1<=d2)if( (day+d2-d1++)%7%6 ) works++;
  return works;
}

太厉害了,看不大懂,能不能注释下还有如果要排除掉var Holiday = ["2013-01-01", "2013-01-02", "2013-01-03","2013-05-01","2013-09-01", "2013-10-01", "2013-10-02", "2013-10-03", "2013-10-04];中的日期,在上面的基础上,有没有比较简洁的方法之前我自己想到的也是
一天天循环去跟数据里的值比较 function check(n,a) {
            for (var i = 0, len = a.length; i < len; i++) {
                if (a[i] == n) {
                    return true;
                }
            }
            return false;
        }

加了算 Holiday 里的日期 var Holiday = ["2013-01-01", "2013-01-02", "2013-01-03","2013-05-01","2013-09-01", "2013-10-01", "2013-10-02", "2013-10-03", "2013-10-04"];

function workdays(d1,d2){
  function toD(d){return new Date(d.replace(/-/g,'/')) }   //转成Date对象
  function ds(d){return d.getTime()/864E5>>0} //天数
  var day,d,d1=toD(d1),d2=toD(d2),d0=d1,works=0,o={},i=0;
  for(var i=0,L=Holiday.length;i<L;i++) o[ ds(toD( Holiday[i]))]=1;
  if(d1>d2){d=d1;d1=d2;d2=d} //确保d1<d2
  day=d1.getDay();  //d1星期
  d1=ds(d1),d2=ds(d2);
  while(d1<=d2)
    if(  (day+d2-d1++)%7%6||o[d1] )works++; //取星期天，六，加Holiday里的
  return works;
}

"2012-01-01"==toD("2012/01/01") 吗是不等的，toD将字符串转Date对象
toD("2012-2-1")==toD("2012-02-01")==toD("2012/01/01") 这样是相等的，所以也支持 "2012-2-1"这格式
  var Holiday = ["2013-01-01", "2013-01-02", "2013-01-03","2013-05-01","2013-09-01", "2013-10-01", "2013-10-02", "2013-10-03", "2013-10-04"];

function workdays(d1,d2){
  function toD(d){return new Date(d.replace(/-/g,'/')) }   //转成Date对象
  function ds(d){return d.getTime()/864E5>>0} //天数
  var day,d,d1=toD(d1),d2=toD(d2),d0=d1,works=0,o={},i=0;
  for(var i=0,L=Holiday.length;i<L;i++) o[ ds(toD( Holiday[i]))]=1;
  if(d1>d2){d=d1;d1=d2;d2=d} //确保d1<d2
  day=d1.getDay();  //d1星期
  d1=ds(d1),d2=ds(d2);
  while(d1<=d2)
    if( (day+d2-d1++)%7%6&&!o[d1-1] )works++; //取星期天，六，加Holiday里的
  return works;
}

workdays('2013-01-01','2013-01-10') =5 ，应该对了：）

呵呵,workdays('2013-01-01','2013-01-10') =4
是对的,
但是workdays('2013-01-01','2013-01-07') =3是不对的

toD("2012-2-1")==toD("2012-02-01")==toD("2012/01/01") 这样是相等的，所以也支持 "2012-2-1"这格式
=============严重理解错我的意思：toD("2012-02-01")!="2012-02-01" 难道你忘了js里月份要比实现小1吗？所以按你的函数toD("2012-02-01")="2012-03-01"

还有你的while()里也有问题
alert(workdays("2013-01-30","2013-02-01"));//结果是3天!!!，而实现上只有一天2013-1-31

alert(workdays("2013-01-30","2013-02-01"));//结果是3天!!!，是正确的啊30 31 1

new Date(year, month, date）这样是时候月份要比实现小1
new Date("yyyy-mm-dd"）这样的时候就不用管了-----------------------------
原是算的是大有问题，再试试 var Holiday = ["2013-01-01", "2013-01-02", "2013-01-03","2013-05-01","2013-09-01", "2013-10-01", "2013-10-02", "2013-10-03", "2013-10-04"];
function workdays(d1,d2){
  function toD(d){return new Date(d.replace(/-/g,'/')) }   //转成Date对象
  function ds(d){return d.getTime()/864E5>>0} //天数
  var day,d,d1=toD(d1),d2=toD(d2),d0=d1,works=0,o={},i=0,L;
  for(i=0,L=Holiday.length;i<L;i++) { o[ ds(toD( Holiday[i]))]=1;};
  if(d1>d2){d=d1;d1=d2;d2=d} //确保d1<d2
  day=d1.getDay();  //d1星期
  d1=ds(d1),d2=ds(d2),i=d2-d1+1;
  while(i--) if( (day+i)%7%6 && !o[d1+i] ) works++; //取星期天，六，加Holiday里的
  return works;
}
alert( workdays('2013-01-01','2013-01-7') )

试了几个情况 ,暂时没有发现问题啊
真是太感谢了.
呵,如果离LZ近,LZ还真放请吃饭来的

<%@ Page Language="C#" AutoEventWireup="true"  CodeFile="Default.aspx.cs" Inherits="_Default"  EnableEventValidation="false"%><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml" >
<head runat="server">
    <title>无标题页</title>
    <script type="text/javascript" src="My97DatePicker/calendar.js" ></script>
    <script type="text/javascript" src="My97DatePicker/config.js" ></script>
    <script type="text/javascript" src="My97DatePicker/WdatePicker.js" ></script>
    <script type="text/javascript" src="js/jquery.js"></script>
    <style type="text/css">
    .disno{ display:none;}
    body{font-size:12px;
    }
    .tx{ border:none; text-align:center;font-family:黑体; font-size:20px;  width:115px; }


    .tx1{ border:none; width: 128px;text-align:center;font-family:黑体; font-size:18px; }
    .inp{ border:1px solid #cccccc; width:100px;}


    </style>
    <script type="text/javascript">        function CheckDate(source) {
            var row_id = source.id.substr(0, source.id.lastIndexOf('_') + 1);
            var textbox1 = document.getElementById(row_id + 'frdt');
            var textbox2 = document.getElementById(row_id + 'todt');
                  var   a=textbox1.value+" 23:59:59";
               a=a.replace("-","/");
               var dateA=new Date(a);
               var dateNow=new Date();
               if (Date.parse(dateNow) - Date.parse(dateA) > 0) {
                   alert("开始日期错误");
                   textbox1.focus();
                   return false;
               }
               if (textbox2.value!= "") {
                   if (textbox1.value > textbox2.value) {
                       alert("结束日期要比开始日期大");
                       return false;                   }
               }               var label = document.getElementById(row_id + 'num');
               label.value = workdays(textbox1.value, textbox2.value)
           }

           var Holiday = ["2013-01-01", "2013-01-02", "2013-01-03", "2013-05-01", "2013-09-01", "2013-10-01", "2013-10-02", "2013-10-03", "2013-10-04"];
           function workdays(d1, d2) {
               function toD(d) { return new Date(d.replace(/-/g, '/')) }   //转成Date对象
               function ds(d) { return d.getTime() / 864E5 >> 0 } //天数
               var day, d, d1 = toD(d1), d2 = toD(d2), d0 = d1, works = 0, o = {}, i = 0, L;
               for (i = 0, L = Holiday.length; i < L; i++) { o[ds(toD(Holiday[i]))] = 1; };
               if (d1 > d2) { d = d1; d1 = d2; d2 = d } //确保d1<d2
               day = d1.getDay();  //d1星期
               d1 = ds(d1), d2 = ds(d2), i = d2 - d1 + 1;
               while (i--) if ((day + i) % 7 % 6 && !o[d1 + i]) works++; //取星期天，六，加Holiday里的
               return works;
           }      </script>
       <style media="print" type="text/css">
.Noprint{display:none;}
.PageNext{page-break-after: always;}
</style>

</head>
<body  >
    <form id="form1" runat="server">

    <asp:ScriptManager ID="ScriptManager1" runat="server" />
      <asp:UpdatePanel ID="UpdatePanel1" runat="server">
    <ContentTemplate>
    <asp:ImageButton ID="ImageButton1" runat="server"  ImageUrl="images/new.gif" CssClass="imgbt" OnClick="ImageButton1_Click"/>
     <asp:ImageButton ID="ImageButton2" runat="server"  ImageUrl="images/del.gif" CssClass="imgbt" OnClick="btnDelete_Click"/>

    <asp:hiddenfield runat="server" id="hfID"></asp:hiddenfield>
        <asp:Label ID="Label1" runat="server" Text="Label"></asp:Label>   <asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="false"  OnSelectedIndexChanged="GridView1_SelectedIndexChanged"   OnRowCreated="GridView1_RowCreate">
   <Columns>
                    <asp:TemplateField HeaderText="NO." ItemStyle-HorizontalAlign="center">
                         <ItemTemplate>
                           <asp:Label runat="server" ID="lblID" Text='<%#Eval("ID") %>'></asp:Label>
                             </ItemTemplate>
                              <ItemStyle HorizontalAlign="center" />
                      </asp:TemplateField>

              <asp:TemplateField HeaderText="开始时间">
               <ItemTemplate>                  <asp:TextBox ID="frdt" runat="server" CssClass="Wdate" Width="120" Text='<%#Eval("frdt")%>'  onchange="CheckDate(this)">
                   </asp:TextBox>
                   </ItemTemplate>
                </asp:TemplateField>                  <asp:TemplateField HeaderText="结束日期">
                 <ItemTemplate>
                    <asp:TextBox ID="todt" runat="server" CssClass="Wdate" Width="120" Text='<%#Eval("todt") %>'   onchange="CheckDate(this)">
                   </asp:TextBox>
                </ItemTemplate>
                </asp:TemplateField>
                   <asp:TemplateField HeaderText="使用个数">
                 <ItemTemplate>
                                       <asp:TextBox ID="num" runat="server"  Text='<%#Eval("num") %>' BorderWidth="0" Width="10"></asp:TextBox>
                </ItemTemplate>
                </asp:TemplateField>
   </Columns>
   </asp:GridView>     </ContentTemplate>
    </asp:UpdatePanel>

    </form>
</body>
</html>

下面是查看的源代码
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">
<head><title>
无标题页
</title>
    <script type="text/javascript" src="My97DatePicker/calendar.js" ></script>
    <script type="text/javascript" src="My97DatePicker/config.js" ></script>
    <script type="text/javascript" src="My97DatePicker/WdatePicker.js" ></script>
    <script type="text/javascript" src="js/jquery.js"></script>
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    .disno{ display:none;}
    body{font-size:12px;
    }
    .tx{ border:none; text-align:center;font-family:黑体; font-size:20px;  width:115px; }


    .tx1{ border:none; width: 128px;text-align:center;font-family:黑体; font-size:18px; }
    .inp{ border:1px solid #cccccc; width:100px;}


    </style>
    <script type="text/javascript">

        function CheckDate(source) {
            var row_id = source.id.substr(0, source.id.lastIndexOf('_') + 1);
            var textbox1 = document.getElementById(row_id + 'frdt');
            var textbox2 = document.getElementById(row_id + 'todt');

            var a = textbox1.value + " 23:59:59";
            a = a.replace("-", "/");
            var dateA = new Date(a);
            var dateNow = new Date();
            if (Date.parse(dateNow) - Date.parse(dateA) > 0) {
                alert("开始日期错误");
                textbox1.focus();
                return false;
            }

            if (textbox2.value != "") {
                if (textbox1.value > textbox2.value) {
                    alert("结束日期要比开始日期大");
                    return false;

                }
            }

            var label = document.getElementById(row_id + 'num');
            label.value = workdays(textbox1.value, textbox2.value)

        }



        var Holiday = ["2013-01-01", "2013-01-02", "2013-01-03", "2013-05-01", "2013-09-01", "2013-10-01", "2013-10-02", "2013-10-03", "2013-10-04"];
        function workdays(d1, d2) {
            function toD(d) { return new Date(d.replace(/-/g, '/')) }   //转成Date对象
            function ds(d) { return d.getTime() / 864E5 >> 0 } //天数
            var day, d, d1 = toD(d1), d2 = toD(d2), d0 = d1, works = 0, o = {}, i = 0, L;
            for (i = 0, L = Holiday.length; i < L; i++) { o[ds(toD(Holiday[i]))] = 1; };
            if (d1 > d2) { d = d1; d1 = d2; d2 = d } //确保d1<d2
            day = d1.getDay();  //d1星期
            d1 = ds(d1), d2 = ds(d2), i = d2 - d1 + 1;
            while (i--) if ((day + i) % 7 % 6 && !o[d1 + i]) works++; //取星期天，六，加Holiday里的
            return works;
        }

    </script>
</head>
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    <input type="hidden" name="hfID" id="hfID" />
        <span id="Label1">Label</span>

   <div>
<table cellspacing="0" rules="all" border="1" id="GridView1" style="border-collapse:collapse;">
<tr>
<th scope="col">NO.</th><th scope="col">开始时间</th><th scope="col">结束日期</th><th scope="col">使用个数</th>
</tr><tr onClick="javascript:__doPostBack('GridView1','Select$0');" style="cursor:hand;">
<td align="center">
                           <span id="GridView1_ctl02_lblID">1</span>
                             </td><td>

                <input name="GridView1$ctl02$frdt" type="text" id="GridView1_ctl02_frdt" class="Wdate" onchange="CheckDate(this)" onclick="WdatePicker({el:$dp.$('txb')})" style="width:120px;" />
                   </td><td>
                    <input name="GridView1$ctl02$todt" type="text" id="GridView1_ctl02_todt" class="Wdate" onchange="CheckDate(this)" onclick="WdatePicker({el:$dp.$('txb1')})" style="width:120px;" />
                </td><td>


                     <input name="GridView1$ctl02$num" type="text" value="0" id="GridView1_ctl02_num" style="border-width:0px;width:10px;" />

                </td>
</tr>
</table>
</div>


</div>

    </form>
</body>
</html>
报的错是

结合fzfei2的方法：<script type="text/javascript">
    var Holiday = ["2013-01-01", "2013-01-02", "2013-01-03","2013-05-01","2013-09-01", "2013-10-01", "2013-10-02", "2013-10-03", "2013-10-04"];
    var ftdt="2013-10-01",todt="2013-10-07";
    alert(get_fun(ftdt,todt));
    function get_fun(bd,ed){
        var arr=[];
        function toD(d) { return new Date(d.replace(/-/g, '/')) }
        var e=toD(ed);
        function tml(t){
            var n=new Date();
            n.setTime(toD(t).getTime()+864E5);
            return n.getFullYear()+"-"+("0"+(n.getMonth()+1)).slice(-2)+"-"+("0"+n.getDate()).slice(-2);
        }
        while (toD(bd)<=e){
            var w=toD(bd).getDay();
            if(w!=0&&w!=6&&Holiday.indexOf(bd)==-1)arr[arr.length]=bd;
            bd=tml(bd);
        }
        //alert(arr);//输出符合条件的日期集合
        return arr.length;//得到日期天数
    }
</script>已经测试通过你上面提到的几个日期，其他日期你测试一下。

本人最讨厌在公共场所晾代码不写注释了。所有自己写了个带注释的.
该问题最关键是要理清不同种日期（节假日，周末，工作日(周一到周五)）这3个集合之间的关系。
相信看了下面的韦恩图，代码谁都会写。

<script>//注：要求所有表示日期的字符串的形式为"2013-01-01"
//var oneDay=24*60*60*1000;
//所有节假日
var Holidays= ["2013-01-01", "2013-01-02", "2013-01-03","2013-05-01","2013-09-01", "2013-10-01", "2013-10-02", "2013-10-03", "2013-10-04"];
var OnWorkWeekends=[]; //所有节假日调整而上班的周末日期
//设置起止日期
var startDate="2013-01-13";
var endDate="2013-01-21";
//function isWeekdays(iDate){ //判断日期是否是工作日
var dt=new Date(iDate);
if(dt.getDay()==0||dt.getDay()==6){
return false;
}
else {
return true;
}
}
function getDatesBetweenTime(dateList,startDate1,endDate1){//返回指定日期集合中处于查询时间段内的日期子集
var dateBetweenTime=new Array();
for(var k=0;k<dateList.length;k++){
if(dateList[k]>=startDate1 && dateList[k]<=endDate1){
dateBetweenTime.push(dateList[k]);
}
}
return dateBetweenTime;
}
//alert(isWeekdays(Date.parse("2013-01-01")));//获得时段内的节假日
var holidays=getDatesBetweenTime(Holidays,startDate,endDate);
//获得时段内的应节假日调整而上班的周末日期
var onWorkWeekends=getDatesBetweenTime(OnWorkWeekends,startDate,endDate); //alert(holidays);
//alert(onWorkWeekends);alert(computeWorkDays(holidays,onWorkWeekends.length,startDate,endDate));
function computeWorkDays(holidays,onWorkWeekendsLen,startDate,endDate){//计算startDate~endDate（包括两个端点）中的工作日期数格式为"2013-01-01" var result=0; //记录结果
var oneDay=24*60*60*1000;
var weekdays=[];
var startDt=Date.parse(startDate);

var totalDays=(Date.parse(endDate)-Date.parse(startDate))/oneDay;
var nextDate=startDt;

//记录查询时间段内所有的属于周一到周五的日期
for(var i=0;i<totalDays;i++){
nextDate+=oneDay;

if(isWeekdays(nextDate)){
weekdays.push(nextDate);//weekdays中存的是日期的毫秒数
}
}
result=weekdays.length;

//剔除weekdays中的节假日
for(var j=0;j<holidays.length;j++){
if(isWeekdays(Date.parse(holidays[j]))){
result--;
}
} return (result+onWorkWeekendsLen);}</script>

如果有些周六  日要算在里面的,改成这样又不对,workd放是周六  日但要算在天数中的
var Holiday = ["2013-01-01", "2013-02-08", "2013-02-11", "2013-02-12", "2013-02-13", "2013-02-14", "2013-04-04", "2013-05-01", "2013-06-12", "2013-09-19", "2013-10-01", "2013-10-02", "2013-10-03"];
        var workd = ["2013-02-02", "2013-02-03"];
        function workdays(d1, d2) {
            function toD(d) { return new Date(d.replace(/-/g, '/')) }   //转成Date对象
            function ds(d) { return d.getTime() / 864E5 >> 0 } //天数
            var day, d, d1 = toD(d1), d2 = toD(d2), d0 = d1, works = 0, o = {}, i = 0, L, p = {};
            for (i = 0, L = Holiday.length; i < L; i++) { o[ds(toD(Holiday[i]))] = 1; };            for (j = 0, W = workd.length; j < W; j++){ p[ds(toD(workd[j]))] = 1; };
            if (d1 > d2) { d = d1; d1 = d2; d2 = d } //确保d1<d2
            day = d1.getDay();  //d1星期
            d1 = ds(d1), d2 = ds(d2), i = d2 - d1 + 1;
            while (i--) if ((day + i) % 7 % 6 && !o[d1 + i]) works++; //取星期天，六，加Holiday里的
            while (j--) {
                if (p[d1 + j]) works++;
            }
            return works;
        }

什么意思，是说workd[] 中的日期规定为工作日？

输入参数为2013-10-02，2013-10-07时答案为0，是因为忽略了一点：时间实际上为
2013-10-02 00：00：00，2013-10-07 00：00：00，所有他们的时差实际上为（7-2）-1=4天，而我们实际上要计算的是5天内的工作天数。另外在循环的起点向后推了一天，这也是个小错误。以前错误的地方我下面用红色文字标识出来了，同时把以前的代码注释在后面。先补个图吧。（看了图大家都会明白的。再有小错误，自己修改，想信不会有了）
<script>//注：要求所有表示日期的字符串的形式为"2013-01-01"
//var oneDay=24*60*60*1000;
//所有节假日
var Holidays= ["2013-01-01", "2013-01-02", "2013-01-03","2013-05-01","2013-09-01", "2013-10-01", "2013-10-02", "2013-10-03", "2013-10-04"];
var OnWorkWeekends=[]; //所有节假日调整而上班的周末日期
//设置起止日期
var startDate="2013-10-02";
var endDate="2013-10-07";
//function isWeekdays(iDate){ //判断日期是否是工作日
var dt=new Date(iDate);
if(dt.getDay()==0||dt.getDay()==6){
return false;
}
else {
return true;
}
}
function getDatesBetweenTime(dateList,startDate1,endDate1){//返回指定日期集合中处于查询时间段内的日期子集
var dateBetweenTime=new Array();
for(var k=0;k<dateList.length;k++){
if(dateList[k]>=startDate1 && dateList[k]<=endDate1){
dateBetweenTime.push(dateList[k]);
}
}
return dateBetweenTime;
}
//alert(isWeekdays(Date.parse("2013-01-01")));//获得时段内的节假日
var holidays=getDatesBetweenTime(Holidays,startDate,endDate);
//获得时段内的应节假日调整而上班的周末日期
var onWorkWeekends=getDatesBetweenTime(OnWorkWeekends,startDate,endDate);//alert(holidays);
//alert(onWorkWeekends);alert(computeWorkDays(holidays,onWorkWeekends.length,startDate,endDate));
function computeWorkDays(holidays,onWorkWeekendsLen,startDate,endDate){//计算startDate~endDate（包括两个端点）中的工作日期数格式为"2013-01-01"var result=0; //记录结果
var oneDay=24*60*60*1000;
var weekdays=[];
var startDt=Date.parse(startDate);var totalDays=(Date.parse(endDate)-Date.parse(startDate))/oneDay+1;/*上次的代码少了+1，少算了一天*/
var nextDate=startDt-oneDay;/*上次的代码中没有-oneDay，而循环是从下一天（nextDate+=oneDay;）开始的，应该是输入参数那一天，所有初始值减一天，即应初始化为开始日期的前一天*/
//记录查询时间段内所有的属于周一到周五的日期
for(var i=0;i<totalDays;i++){
nextDate+=oneDay;if(isWeekdays(nextDate)){
weekdays.push(nextDate);//weekdays中存的是日期的毫秒数
}
}
result=weekdays.length;//剔除weekdays中的节假日
for(var j=0;j<holidays.length;j++){
if(isWeekdays(Date.parse(holidays[j]))){
result--;
}
}return (result+onWorkWeekendsLen);}</script>

调试易

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解决方案 »

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怎么根据两个日期得到除节假日周末外的天数