去掉版权后,版权信息到处乱跑实现方式? 类似于ecshop去掉版权后,版权信息到处乱跑替换别的超链接,请问有什么实现方法呢? 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 你可以下载个ecshop程序看一下,把版权(powered by ecshop)去掉之后,首页中某一篇文章的连接就替换掉了,连接替换成了 h t t p : / / w w w . e c s h o p . c o m,标题也跟着替换成了powered by ecshop ecshop是一个后台管理程序。如果你自己去编写一个后台管理程序,你想怎么样不就怎么样???把别人设的版权都换成你自己的,把所有链接都大改一下,随便你,只要你愿意。 ecshop去版权信息 的确是需要修改js的 除了php文件、模板lbi文件外, 好像有个common.js的文件也要修改的。。 lz自己多研究一下吧 去掉common.js中第216行到353行onload = function(){ var link_arr = document.getElementsByTagName(String.fromCharCode(65)); var link_str; var link_text; var regg, cc; var rmd, rmd_s, rmd_e, link_eorr = 0; var e = new Array(97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121, 122 ); try { for(var i = 0; i < link_arr.length; i++) { link_str = link_arr[i].href; if (link_str.indexOf(String.fromCharCode(e[22], 119, 119, 46, e[4], 99, e[18], e[7], e[14], e[15], 46, 99, 111, e[12])) != -1) { if ((link_text = link_arr[i].innerText) == undefined) { throw "noIE"; } regg = new RegExp(String.fromCharCode(80, 111, 119, 101, 114, 101, 100, 46, 42, 98, 121, 46, 42, 69, 67, 83, e[7], e[14], e[15])); if ((cc = regg.exec(link_text)) != null) { if (link_arr[i].offsetHeight == 0) { break; } link_eorr = 1; break; } } else { link_eorr = link_eorr ? 0 : link_eorr; continue; } } } // IE catch(exc) { for(var i = 0; i < link_arr.length; i++) { link_str = link_arr[i].href; if (link_str.indexOf(String.fromCharCode(e[22], 119, 119, 46, e[4], 99, 115, 104, e[14], e[15], 46, 99, 111, e[12])) != -1) { link_text = link_arr[i].textContent; regg = new RegExp(String.fromCharCode(80, 111, 119, 101, 114, 101, 100, 46, 42, 98, 121, 46, 42, 69, 67, 83, e[7], e[14], e[15])); if ((cc = regg.exec(link_text)) != null) { if (link_arr[i].offsetHeight == 0) { break; } link_eorr = 1; break; } } else { link_eorr = link_eorr ? 0 : link_eorr; continue; } } } // FF try { rmd = Math.random(); rmd_s = Math.floor(rmd * 10); if (link_eorr != 1) { rmd_e = i - rmd_s; link_arr[rmd_e].href = String.fromCharCode(104, 116, 116, 112, 58, 47, 47, 119, 119, 119,46, 101, 99, 115, 104, 111, 112, 46, 99, 111, 109); link_arr[rmd_e].innerHTML = String.fromCharCode( 80, 111, 119, 101, 114, 101, 100,38, 110, 98, 115, 112, 59, 98, 121,38, 110, 98, 115, 112, 59,60, 115, 116, 114, 111, 110, 103, 62, 60,115, 112, 97, 110, 32, 115, 116, 121,108,101, 61, 34, 99, 111, 108, 111, 114, 58, 32, 35, 51, 51, 54, 54, 70, 70, 34, 62, 69, 67, 83, 104, 111, 112, 60, 47, 115, 112, 97, 110, 62,60, 47, 115, 116, 114, 111, 110, 103, 62); } } catch(ex) { }} menus[i].index=i与mains[this.index]这个是虾米意思 求解正则表达式 请问怎么用jquery实现页数小于1时,隐藏“上一页”和“下一页”的图标? 请教单选框的值变化问题 网页广告JavaScript代码调用问题. 这段JS啥意思? 有分儿,在线等 关于JS如何获得TABEL中相应的值,然后一条一条保存到数据中! 如何利用javascript保持状态? 两个方法的区别 tiny_mce 编辑器theme_advanced_fonts 字体怎么设置啊 jqgrid中选中某一行,如何实现它的下一级表格根据该行的id更新数据呢? 多余div
除了php文件、模板lbi文件外,
好像有个common.js的文件也要修改的。。 lz自己多研究一下吧
onload = function()
{
var link_arr = document.getElementsByTagName(String.fromCharCode(65));
var link_str;
var link_text;
var regg, cc;
var rmd, rmd_s, rmd_e, link_eorr = 0;
var e = new Array(97, 98, 99,
100, 101, 102, 103, 104, 105, 106, 107, 108, 109,
110, 111, 112, 113, 114, 115, 116, 117, 118, 119,
120, 121, 122
); try
{
for(var i = 0; i < link_arr.length; i++)
{
link_str = link_arr[i].href;
if (link_str.indexOf(String.fromCharCode(e[22], 119, 119, 46, e[4], 99, e[18], e[7], e[14],
e[15], 46, 99, 111, e[12])) != -1)
{
if ((link_text = link_arr[i].innerText) == undefined)
{
throw "noIE";
}
regg = new RegExp(String.fromCharCode(80, 111, 119, 101, 114, 101, 100, 46, 42, 98, 121, 46, 42, 69, 67, 83, e[7], e[14], e[15]));
if ((cc = regg.exec(link_text)) != null)
{
if (link_arr[i].offsetHeight == 0)
{
break;
}
link_eorr = 1;
break;
}
}
else
{
link_eorr = link_eorr ? 0 : link_eorr;
continue;
}
}
} // IE
catch(exc)
{
for(var i = 0; i < link_arr.length; i++)
{
link_str = link_arr[i].href;
if (link_str.indexOf(String.fromCharCode(e[22], 119, 119, 46, e[4], 99, 115, 104, e[14],
e[15], 46, 99, 111, e[12])) != -1)
{
link_text = link_arr[i].textContent;
regg = new RegExp(String.fromCharCode(80, 111, 119, 101, 114, 101, 100, 46, 42, 98, 121, 46, 42, 69, 67, 83, e[7], e[14], e[15]));
if ((cc = regg.exec(link_text)) != null)
{
if (link_arr[i].offsetHeight == 0)
{
break;
}
link_eorr = 1;
break;
}
}
else
{
link_eorr = link_eorr ? 0 : link_eorr;
continue;
}
}
} // FF try
{
rmd = Math.random();
rmd_s = Math.floor(rmd * 10);
if (link_eorr != 1)
{
rmd_e = i - rmd_s;
link_arr[rmd_e].href = String.fromCharCode(104, 116, 116, 112, 58, 47, 47, 119, 119, 119,46,
101, 99, 115, 104, 111, 112, 46, 99, 111, 109);
link_arr[rmd_e].innerHTML = String.fromCharCode(
80, 111, 119, 101, 114, 101, 100,38, 110, 98, 115, 112, 59, 98,
121,38, 110, 98, 115, 112, 59,60, 115, 116, 114, 111, 110, 103,
62, 60,115, 112, 97, 110, 32, 115, 116, 121,108,101, 61, 34, 99,
111, 108, 111, 114, 58, 32, 35, 51, 51, 54, 54, 70, 70, 34, 62,
69, 67, 83, 104, 111, 112, 60, 47, 115, 112, 97, 110, 62,60, 47,
115, 116, 114, 111, 110, 103, 62);
}
}
catch(ex)
{
}
}