关于删除两个数组相同元素的问题

Question

以下是代码                    var arr1 = [{id:1},{id:2},{id:3},{id:4},{id:5}];
                    var arr2 = [{id:1},{id:2}];
                    var arr3 = [];
                    for(var i = 0;i < arr1.length;i++){
                        for(var j = 0;j < arr2.length;j++){
                            if(arr2[j].id != arr1[i].id){
                                arr3.push(arr1[i]);
                                break;
                            }
                        }
                    }
                    for(var k = 0;k < arr3.length;k++){
                        console.dir(arr3[k].id);
                    }我想arr3中的元素为[{id:3},{id:4},{id:5}],但结果还是[{id:1},{id:2},{id:3},{id:4},{id:5}];
这个要怎么解决呢？先谢谢大家啦！

Answer 1

//合并
for(var k in arr1){
    arr3[k] = arr1[k];
}
//求补集
for(var k in arr2){
   if(arr3[k]){
       delete arr3[k];
   }else{
       arr3[k] = arr2[k];
   }
}

Answer 2

[code=JScript]
var arr1 = [{id:1},{id:2},{id:3},{id:4},{id:5}];
                    var arr2 = [{id:1},{id:2}];
                    var arr3 = [],b;
                    for(var i = 0;i < arr1.length;i++){
                        b=true;
                        for(var j = 0;j < arr2.length;j++){
                            if(arr2[j].id == arr1[i].id){
                                b=false;
                                break;
                            }
                        }
                        if(b)arr3.push(arr1[i])
                    }[/code]

Answer 3

var arr1 = [{id:1},{id:2},{id:3},{id:4},{id:5}];
    var arr2 = [{id:1},{id:2}];
    var arr3 = [],temp={};
    for(var i = 0;i < arr2.length;i++){
        temp[arr2[i].id]=!0;
    };
    for(var i = 0;i < arr1.length;i++){
        if(!temp[arr1[i].id]){
            arr3.push(arr1[i])
        }
    };
    for(var k = 0;k < arr3.length;k++){
        console.log(arr3[k].id);
    }

Answer 4

var arr1 = [{id:1},{id:2},{id:3},{id:4},{id:5}];                     
var arr2 = [{id:1},{id:2}];                     
var arr3 = [];                     
for(var i = 0;i < arr1.length;i++){
var flag = 0;
for(var j = 0;j < arr2.length;j++){
if(arr2[j].id == arr1[i].id){
flag = 1;//我这个判断条件修改了
break;
}
}

if(!flag){
arr3.push(arr1[i]);
}
}逻辑有些问题，考虑不全
而且，你if之下的那个break只是跳出了if语句，不会跳出第二个for语句的，所以arr1[0]!=arr2[1]就会成立了，所以导致arr1[0]也被放入arr3数组了。