求一个正则表达式

Question

0001|3,0002|4,0003|77,0004,0005|99 能匹配出0001|3两个逗号间的字符

Answer 1

//直接用字符串分割操作
var str='0001|3,0002|4,0003|77,0004,0005|99';
var arr1=str.split(','),arr2;
for(var i=0;i<arr1.length;i++){
    arr2=arr1[i].split('|');
    alert(arr2[0]+'：'+arr2[1])
}

Answer 2

<script type="text/javascript">
Array.prototype.inArray=function (value){for (var i=0;i<this.length;i++){if (this[i] == value){return true;}}return false};
function replaceNo(a,b){
    var arr1=b.split(','),arr2,arr3=a.split(','),arr4=new Array();
    for(var i=0;i<arr1.length;i++){
        arr2=arr1[i].split('|');
        if(arr3.inArray(arr2[0])){
            arr4.push(arr2[0]);
        }else{
            arr4.push(arr1[i]);
        }
    };
    return arr4.join(',');
}
var str=replaceNo('0001,0008','0001|1,0005|7,0008|9');
alert(str);
</script>有什么不同，自己加点判断就是了
replaceNo(a/*需要匹配的编号,多个编号以逗号分隔*/,b/*原始的列表*/)

Answer 3

var r,
    s='0001|3,0002|4,0003|77,0004,0005|99',
    no=['0001','0002','0003','0004'];for(var i=no.length-1;i>=0;i--){
    r=new RegExp('(\\\\s+|^|,)('+no[i]+')\\|\\d+(\\\\s+|$|,)','gi');
    alert('替换编号\t：'+no[i]+'\r\n原字符串\t：'+s+'\r\n替换  后\t：'+s.replace(r,'$1$2$3'))
}

Answer 4

var key="0001";
var reg=new RegExp(key+"(\|\d+)?,","g");
yourhtml=yourhtml.replace(reg,"");

Answer 5

多谢tim,不过你的方法测试不通过s="000001|5,000002|4,000003|77,000004,000005|99"; 
var key="000001";
var reg=new RegExp(key+"(\|\d+)?,","g");
alert('替换编号\t：'+key+'\r\n原字符串\t：'+s+'\r\n替换 后\t：'+s.replace(reg,""));