例如 移除以下字符串,该如何写正则"level":1,
"tId":"menutree_2",
"parentTId":"menutree_1",
"open":false,
"isParent":false,
"zAsync":true,
"isFirstNode":true,
"isLastNode":false,
"isAjaxing":false,
"checked":true,
"checkedOld":false,
"nocheck":false,
"chkDisabled":false,
"halfCheck":false,
"check_Child_State":-1,
"check_Focus":false
"tId":"menutree_2",
"parentTId":"menutree_1",
"open":false,
"isParent":false,
"zAsync":true,
"isFirstNode":true,
"isLastNode":false,
"isAjaxing":false,
"checked":true,
"checkedOld":false,
"nocheck":false,
"chkDisabled":false,
"halfCheck":false,
"check_Child_State":-1,
"check_Focus":false
"tId":"menutree_2",
"parentTId":"menutree_1",
"open":false,
"isParent":false,
"zAsync":true,
"isFirstNode":true,
"isLastNode":false,
"isAjaxing":false,
"checked":true,
"checkedOld":false,
"nocheck":false,
"chkDisabled":false,
"halfCheck":false,
"check_Child_State":-1,
"check_Focus":false
};
//如果需要判断值,则使用以下的
if(_json.level==1){delete _json.level};
//如果删除一个指定元素,不需要判断值,则使用以下的
delete _json.check_Focus;
for(i in _json)
{
alert(i+":"+_json[i])
}
delete _json.check_Focus;我都写得明明白白了,你好歹看得仔细点
delete _json.tId
我这样子写但是没有作用function deleteNode(nodes){
delete nodes.level;
delete nodes.tId;
delete nodes.parentTId;
delete nodes.open;
delete nodes.isParent;
delete nodes.zAsync;
delete nodes.isFirstNode;
delete nodes.isLastNode;
delete nodes.isAjaxing;
delete nodes.checked;
delete nodes.checkedOld;
delete nodes.nocheck;
delete nodes.chkDisabled;
delete nodes.halfCheck;
delete nodes.check_Child_State;
delete nodes.check_Focus;
return nodes;
}
再说明下 源json 对象是 有很多层级结构的 比如一个节点地下还有多个 children的节点,每个节点都有上面的属性。
"tId":"menutree_2",
"parentTId":"menutree_1",
"open":false,
"isParent":false,
"zAsync":true,
"isFirstNode":true,
"isLastNode":false,
"isAjaxing":false,
"checked":true,
"checkedOld":false,
"nocheck":false,
"chkDisabled":false,
"halfCheck":false,
"check_Child_State":-1,
"check_Focus":false
};
function deleteNode(nodes){
delete nodes.level;
delete nodes.tId;
delete nodes.parentTId;
delete nodes.open;
delete nodes.isParent;
delete nodes.zAsync;
delete nodes.isFirstNode;
delete nodes.isLastNode;
delete nodes.isAjaxing;
delete nodes.checked;
delete nodes.checkedOld;
delete nodes.nocheck;
delete nodes.chkDisabled;
delete nodes.halfCheck;
delete nodes.check_Child_State;
delete nodes.check_Focus;
return nodes;
}
deleteNode(_json);////每去掉其中一个元素的delete,下面的alert即可显示这个元素的键/值;如果全部去除,则下面代码失效for(i in _json)
{
alert(i+":"+_json[i])
}哪里会没有用,是你自己不知道正确的用法而已。自己去试吧