下面这段代码是按照W3C上写的,不过好像chrome不支持,有其他办法吗?
<script type="text/javascript">
var xmlDoc=null;
try{
xmlDoc=new ActiveXObject("Microsoft.XMLDOM");
}catch(e){
try {
xmlDoc = document.implementation.createDocument("", "", null);
}catch(ee){ee.message}
}
xmlDoc.async=false;
xmlDoc.load("XML_001.xml");
var username=xmlDoc.getElementsByTagName("username")[0].childNodes[0].nodeValue;
document.write(username);
</script>
<script type="text/javascript">
var xmlDoc=null;
try{
xmlDoc=new ActiveXObject("Microsoft.XMLDOM");
}catch(e){
try {
xmlDoc = document.implementation.createDocument("", "", null);
}catch(ee){ee.message}
}
xmlDoc.async=false;
xmlDoc.load("XML_001.xml");
var username=xmlDoc.getElementsByTagName("username")[0].childNodes[0].nodeValue;
document.write(username);
</script>
<script type="text/javascript">
var xmlDoc = null;
var xml = "XML_001.xml";
if (window.ActiveXObject) {
xmlDoc = new ActiveXObject('Microsoft.XMLDOM');
xmlDoc.async = false;
xmlDoc.load(xml);
} else if (document.implementation && document.implementation.createDocument) {
try{
xmlDoc = document.implementation.createDocument('', '', null);
xmlDoc.async = false;
xmlDoc.load(xml);
} catch(e){
var xmlhttp = new window.XMLHttpRequest();
xmlhttp.open("GET",xml,false);
xmlhttp.send(null);
xmlDoc = xmlhttp.responseXML.documentElement;
}
}
var username=xmlDoc.getElementsByTagName("username")[0].childNodes[0].nodeValue;
</script>
{
var xmlhttp;
if( window.XMLHttpRequest )
xmlhttp = new XMLHttpRequest();
else{
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.open('GET', url);
xmlhttp.onreadystatechange = function(){
if( xmlhttp.readyState==4 && xmlhttp.status==200 ){
return xmlhttp.responseXML;
}
}
xmlhttp.send();
}