js代码。鼠标滑过图片,显示图片大图在网页上,现在存在这样一个问题,网页中只有那几张图片我想实现这个效果,其他的不想实现,思路是在特定的图片上加一些标记,可是怎么弄js代码啊?对这个不熟。谢谢大家帮忙啦源码送上<script type="text/javascript">
window.onload = function ()
{
var aLi = document.getElementsByTagName("li");
var oBig = document.getElementById("big");
var oLoading = oBig.getElementsByTagName("div")[0];
var i = 0;
for (i = 0; i < aLi.length; i++)
{
aLi[i].index = i;
//鼠标划过, 预加载图片插入容器并显示
aLi[i].onmouseover = function ()
{
var oImg = document.createElement("img");
//图片预加载
var img = new Image();
img.src = oImg.src = aLi[this.index].getElementsByTagName("img")[0].src.replace(".jpg","_big.jpg");
//插入大图片
oBig.appendChild(oImg);
//鼠标移过样式
this.className = "active";
//显示big
oBig.style.display = oLoading.style.display = "block";
//判断大图是否加载成功
img.complete ? oLoading.style.display = "none" : (oImg.onload = function() {oLoading.style.display = "none";})
};
//鼠标移动, 大图容器跟随鼠标移动
aLi[i].onmousemove = function (event)
{
var event = event || window.event;
var iWidth = document.documentElement.offsetWidth - event.clientX;
//设置big的top值
oBig.style.top = event.clientY + 20 + "px";
//设置big的left值, 如果右侧显示区域不够, 大图将在鼠标左侧显示.
oBig.style.left = (iWidth < oBig.offsetWidth + 10 ? event.clientX - oBig.offsetWidth - 10 : event.clientX + 10) + "px";
};
//鼠标离开, 删除大图并隐藏大图容器
aLi[i].onmouseout = function ()
{
this.className = "";
oBig.style.display = "none";
//移除大图片
oBig.removeChild(oBig.lastChild)
}
}
};
</script>
window.onload = function ()
{
var aLi = document.getElementsByTagName("li");
var oBig = document.getElementById("big");
var oLoading = oBig.getElementsByTagName("div")[0];
var i = 0;
for (i = 0; i < aLi.length; i++)
{
aLi[i].index = i;
//鼠标划过, 预加载图片插入容器并显示
aLi[i].onmouseover = function ()
{
var oImg = document.createElement("img");
//图片预加载
var img = new Image();
img.src = oImg.src = aLi[this.index].getElementsByTagName("img")[0].src.replace(".jpg","_big.jpg");
//插入大图片
oBig.appendChild(oImg);
//鼠标移过样式
this.className = "active";
//显示big
oBig.style.display = oLoading.style.display = "block";
//判断大图是否加载成功
img.complete ? oLoading.style.display = "none" : (oImg.onload = function() {oLoading.style.display = "none";})
};
//鼠标移动, 大图容器跟随鼠标移动
aLi[i].onmousemove = function (event)
{
var event = event || window.event;
var iWidth = document.documentElement.offsetWidth - event.clientX;
//设置big的top值
oBig.style.top = event.clientY + 20 + "px";
//设置big的left值, 如果右侧显示区域不够, 大图将在鼠标左侧显示.
oBig.style.left = (iWidth < oBig.offsetWidth + 10 ? event.clientX - oBig.offsetWidth - 10 : event.clientX + 10) + "px";
};
//鼠标离开, 删除大图并隐藏大图容器
aLi[i].onmouseout = function ()
{
this.className = "";
oBig.style.display = "none";
//移除大图片
oBig.removeChild(oBig.lastChild)
}
}
};
</script>
if(this.className=='nopic'){return;}
1:给所有需执行效果的li加上一个非标准化的标记,比如:IsPlay='1'
2:循环体绑定事件之前判断是否IsPlay=="1",不是则不绑定事件
方法二:
1:你的老思路,需要执行效果的li中加上一个虚拟样式,比如 isplay
2:鼠标经过时对样式的操作不应该是this.className='active',你这样赋值就完全覆盖样式了,应该是附加active
3:鼠标离开时对样式的操作不应该是this.className='',而应该是移除active样式,以保证结构的完整性