js中面向对象写法

Question

function createPicMove(a, b, c) {
 var h = function (k, n, m, l) {
        this._slider = g(n);
        this._container = g(k);
        this._timer = null;
        this._count = Math.abs(m);
        this._target = 0;
        this._t = this._b = this._c = 0;
        this.Index = 0;
        this.SetOptions(l);
        this.Auto = !!this.options.Auto;
        this.Duration = Math.abs(this.options.Duration);
        this.Time = Math.abs(this.options.Time);
        this.Pause = Math.abs(this.options.Pause);
        this.Tween = this.options.Tween;
        this.onStart = this.options.onStart;
        this.onFinish = this.options.onFinish;
        var j = !!this.options.Vertical;
        this._css = j ? "top" : "left";
        var o = f(this._container).position;
        o == "relative" || o == "absolute" || (this._container.style.position = "relative");
        this._container.style.overflow = "hidden";
        this._slider.style.position = "absolute";
        this.Change = this.options.Change ? this.options.Change : this._slider[j ? "offsetHeight" : "offsetWidth"] / this._count
    };
    h.prototype = {
        SetOptions: function (j) {
            this.options = {
                Vertical: true,
                Auto: true,
                Change: 0,
                Duration: 50,
                Time: 10,
                Pause: 4000,
                onStart: function () { },
                onFinish: function () { },
                Tween: e.Quart.easeOut
            };
            d(this.options, j || {})
        },
        Run: function (j) {
            j == undefined && (j = this.Index);
            j < 0 && (j = this._count - 1) || j >= this._count && (j = 0);
            this._target = -Math.abs(this.Change) * (this.Index = j);
            this._t = 0;
            this._b = parseInt(f(this._slider)[this.options.Vertical ? "top" : "left"]);
            this._c = this._target - this._b;
            this.onStart();
            this.Move()
        },
        Move: function () {
            clearTimeout(this._timer);
            if (this._c && this._t < this.Duration) {
                this.MoveTo(Math.round(this.Tween(this._t++, this._b, this._c, this.Duration)));
                this._timer = setTimeout(i(this, this.Move), this.Time)
            } else {
                this.MoveTo(this._target);
                this.Auto && (this._timer = setTimeout(i(this, this.Next), this.Pause))
            }
        },
        MoveTo: function (j) {
            this._slider.style[this._css] = j + "px"
        },
        Next: function () {
            this.Run(++this.Index)
        },
        Previous: function () {
            this.Run(--this.Index)
        },
        Stop: function () {
            clearTimeout(this._timer);
            this.MoveTo(this._target)
        }
    };
    return new h(a, b, c, {
        Vertical: false
    })
}本人菜鸟，想问下各位，如何触发 Next 、Previous函数。
先谢谢

Answer 1

  <script type="text/javascript">
        var picMove = createPicMove("参数列表");
        picMove.Next();
        picMove.Previous();
  
    </script>

Answer 2

创建实例然后通过实例调用
var o=new createPicMove(/*a,b,c参数的值*/)
o.Next();
o.Previouse()

Answer 3

<script type="text/javascript">
function Demo(){
var test={
SayHello: function()  //定义方法
{
alert("Hello");
}
}
}
var obj=new Demo();
window.onload=obj.SayHello;
</script>这样不执行。

Answer 4

<script type="text/javascript">
function Demo(){
var test={
SayHello: function()  //定义方法
{
alert("Hello");
}
}
}
var obj=new Demo();
window.onload=obj.SayHello();
</script>

Answer 5

你这个是类似于工厂函数
createPicMove().Previous()就可以调用
function aa(){
var o = function(){
this.name = "深蓝";
}
o.prototype = {
previous : function(){
alert(this.name)
}
}
return new o();
}

var obj = aa();
obj.previous()