错误信息:TypeError: b.isEmptyObject is not a function
数据:var mydata = [ {id:"1",invdate:"2007-10-01",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"}, {id:"2",invdate:"2007-10-02",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"}];jQueryjqGrid
数据:var mydata = [ {id:"1",invdate:"2007-10-01",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"}, {id:"2",invdate:"2007-10-02",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"}];jQueryjqGrid
解决方案 »
- 当input中属性name的定义和事件名相同时无法调用到事件
- 为什么要encodeURI(url)两次才不会出现乱码?
- js的惰性匹配问题
- 好难哦,javascript与vbscript好多函数都没的啊?谁帮我反成VBSCRIPT的啊谢谢啦.!!
- 求解 select 下面的option 注册onmonseover onmonseout事件,求JS高手
- 关于数组的问题
- 求助:ie状态条
- 紧急求助关于用Javascipt编写表单提交的问题
- 解决此问题,马上给分。
- 验证数据,包括小数点,如何做?(正则表达式)在线等着
- js中用dwr如何获取java中List<List<DATA>>的值
- 急,js设置下拉列表框默认值
js: jQuery("#list4").jqGrid({
datatype: "local",
colNames:['Inv No','Date', '客户', 'Amount','Tax','Total','Notes'],
colModel:[
{name:'id',index:'id', width:90,sorttype:"int"},
{name:'Date',index:'invdate', width:110, jsonmap:"invdate"},
{name:'name',index:'name', width:100},
{name:'amount',index:'amount', width:80, align:"right"},
{name:'tax',index:'tax', width:80, align:"right"},
{name:'total',index:'total', width:80,align:"right"},
{name:'note',index:'note', width:150, sortable:false}
],
multiselect: true,
caption: "Manipulating Array Data"
});
jQuery("#list4").jqGrid({
datatype: "local",
colNames:['Inv No','Date', '客户', 'Amount','Tax','Total','Notes'],
colModel:[
{name:'id',index:'id', width:90,sorttype:"int"},
{name:'Date',index:'invdate', width:110, jsonmap:"invdate"},
{name:'name',index:'name', width:100},
{name:'amount',index:'amount', width:80, align:"right"},
{name:'tax',index:'tax', width:80, align:"right"},
{name:'total',index:'total', width:80,align:"right"},
{name:'note',index:'note', width:150, sortable:false}
],
multiselect: true,
caption: "Manipulating Array Data"
});
var mydata = [
{id:"1",date:"2007-10-01",name:"test",note:"note",amount:"200.00",tax:"10.00",total:"210.00"},
{id:"2",date:"2007-10-02",name:"test2",note:"note2",amount:"300.00",tax:"20.00",total:"320.00"}
];
for(var i=0;i<=mydata.length;i++) {
$("#list4").jqGrid('addRowData',i+1,mydata[i]);
}
<script src="http://code.jquery.com/jquery-migrate-1.0.0.js"></script>
问题发现了,一定要引入上面两个js文件,我还没发现怎么下载jquery-migrate-1.0.0.js这个文件,且下载了jquery-latest.js文件,但不能引入,一定要用上面的src="http://code.jquery.com/jquery-latest.js,不知道原因