一个函数内,同一个变量被声明了2次,用于不同的元素,会冲突吗?
html代码:<div id="dome1">dome1</div>
<div id="dome2">dome2</div>
js代码:
function func(){
var elem = document.getElementById("dome1");
elem.style.color = "red";
var elem = document.getElementById("dome2");
elem.style.color = "blue";
alert(elem.innerHTML);
}
window.onload = func;
想知道上面的elem为什么没有被下面的elem重置?JavaScript函数变量
html代码:<div id="dome1">dome1</div>
<div id="dome2">dome2</div>
js代码:
function func(){
var elem = document.getElementById("dome1");
elem.style.color = "red";
var elem = document.getElementById("dome2");
elem.style.color = "blue";
alert(elem.innerHTML);
}
window.onload = func;
想知道上面的elem为什么没有被下面的elem重置?JavaScript函数变量
var elem = document.getElementById("dome2"); 其实就等于elem = document.getElementById("dome2");
var elem = document.getElementById("dome1");
var elem = document.getElementById("dome2");
elem.style.color = "red";
elem.style.color = "blue";
alert(elem.innerHTML);
}
window.onload = func;
我在<dom编程艺术>这本书上看到的例子,是不是不应该这样写呢?
var elem = document.getElementById("dome1");// 得到dome1元素
var elem = document.getElementById("dome2");//得到dome2元素
elem.style.color = "red";//dome2元素字体颜色为red
elem.style.color = "blue";//dome2元素字体颜色为blue
alert(elem.innerHTML);//显示dome2内的html