不会，如何将下面JS程序修改一两个参数实现一次移动和停顿都显示满框列表？

Question

<script language="JavaScript1.2">/*
Pausing updown message scroller- 
Last updated: 99/07/05 (Bugs fixed, ability to specify background image for scroller)powered by 25175.netFor full source code, installation instructions,
100's more DHTML scripts, and Terms Of
Use, visit dynamicdrive.com
*///这里配置滚动字幕的属性
var scrollerwidth=220
var scrollerheight=180
var scrollerbgcolor='#ffdfd0'
//set below to '' if you don't wish to use a background image
var scrollerbackground='scrollerback.gif'//修改下面的文字及文字所指向的链接
var messages=new Array()
messages[0]="<font face='Arial'><a href='../../index.asp'>回到首页仔细看看，看看微风吹过竹叶摇动的效果</a></font>"
messages[1]="<font face='Arial'><a href='../wytx.htm'>请到本站的网页特效区看看，这里有大量的网页特效供你选择</a></font>"
messages[2]="<font face='Arial'><a href='../../bzlt/index.asp'>如果你在游览本站时有什么问题，请到本站的论坛发表看法</a></font>"
messages[3]="<font face='Arial'><a href='../../index.asp'>回到首页仔细看看，看看微风吹过竹叶摇动的效果</a></font>"
messages[4]="<font face='Arial'><a href='../wytx.htm'>请到本站的网页特效区看看，这里有大量的网页特效供你选择</a></font>"
messages[5]="<font face='Arial'><a href='../../bzlt/index.asp'>如果你在游览本站时有什么问题，请到本站的论坛发表看法</a></font>"
///////不要修改下面的内容///////////////////////if (messages.length>1)
i=2
else
i=0function move1(whichlayer){
tlayer=eval(whichlayer)
if (tlayer.top>0&&tlayer.top<=5){
tlayer.top=0
setTimeout("move1(tlayer)",3000)
setTimeout("move2(document.main.document.second)",3000)
return
}
if (tlayer.top>=tlayer.document.height*-1){
tlayer.top-=5
setTimeout("move1(tlayer)",100)
}
else{
tlayer.top=scrollerheight
tlayer.document.write(messages[i])
tlayer.document.close()
if (i==messages.length-1)
i=0
else
i++
}
}function move2(whichlayer){
tlayer2=eval(whichlayer)
if (tlayer2.top>0&&tlayer2.top<=5){
tlayer2.top=0
setTimeout("move2(tlayer2)",3000)
setTimeout("move1(document.main.document.first)",3000)
return
}
if (tlayer2.top>=tlayer2.document.height*-1){
tlayer2.top-=5
setTimeout("move2(tlayer2)",100)
}
else{
tlayer2.top=scrollerheight
tlayer2.document.write(messages[i])
tlayer2.document.close()
if (i==messages.length-1)
i=0
else
i++
}
}function move3(whichdiv){
tdiv=eval(whichdiv)
if (tdiv.style.pixelTop>0&&tdiv.style.pixelTop<=5){
tdiv.style.pixelTop=0
setTimeout("move3(tdiv)",3000)
setTimeout("move4(second2)",3000)
return
}
if (tdiv.style.pixelTop>=tdiv.offsetHeight*-1){
tdiv.style.pixelTop-=5
setTimeout("move3(tdiv)",100)
}
else{
tdiv.style.pixelTop=scrollerheight
tdiv.innerHTML=messages[i]
if (i==messages.length-1)
i=0
else
i++
}
}function move4(whichdiv){
tdiv2=eval(whichdiv)
if (tdiv2.style.pixelTop>0&&tdiv2.style.pixelTop<=5){
tdiv2.style.pixelTop=0
setTimeout("move4(tdiv2)",3000)
setTimeout("move3(first2)",3000)
return
}
if (tdiv2.style.pixelTop>=tdiv2.offsetHeight*-1){
tdiv2.style.pixelTop-=5
setTimeout("move4(second2)",100)
}
else{
tdiv2.style.pixelTop=scrollerheight
tdiv2.innerHTML=messages[i]
if (i==messages.length-1)
i=0
else
i++
}
}function startscroll(){
if (document.all){
move3(first2)
second2.style.top=scrollerheight
second2.style.visibility='visible'
}
else if (document.layers){
document.main.visibility='show'
move1(document.main.document.first)
document.main.document.second.top=scrollerheight+5
document.main.document.second.visibility='show'
}
}window.onload=startscroll</script> 
<ilayer id="main" width=&{scrollerwidth}; height=&{scrollerheight}; bgColor=&{scrollerbgcolor}; background=&{scrollerbackground}; visibility=hide>
<layer id="first" left=0 top=1 width=&{scrollerwidth};>
<script language="JavaScript1.2">
if (document.layers)
document.write(messages[0])
</script>
</layer><layer id="second" left=0 top=0 width=&{scrollerwidth}; visibility=hide>
<script language="JavaScript1.2">
if (document.layers)
document.write(messages[1])
</script>
</layer></ilayer><script language="JavaScript1.2">
if (document.all){
document.writeln('<span id="main2" style="position:relative;width:'+scrollerwidth+';height:'+scrollerheight+';overflow:hiden;background-color:'+scrollerbgcolor+' ;background-image:url('+scrollerbackground+')">')
document.writeln('<div style="position:absolute;width:'+scrollerwidth+';height:'+scrollerheight+';clip:rect(0 '+scrollerwidth+' '+scrollerheight+' 0);left:0;top:0">')
document.writeln('<div id="first2" style="position:absolute;width:'+scrollerwidth+';left:0;top:1;">')
document.write(messages[0])
document.writeln('</div>')
document.writeln('<div id="second2" style="position:absolute;width:'+scrollerwidth+';left:0;top:0;visibility:hidden">')
document.write(messages[1])
document.writeln('</div>')
document.writeln('</div>')
document.writeln('</span>')
}
</script>

Answer 1

下面这段在末尾的时候不能无缝自动接续。而是在末尾的时候跳了一下转到开头，只需要改动一下能无缝自动接续就行。
<div id="mq" style="width:100%;height:18px;overflow:hidden;border:1px solid #ffffff" onmouseover="iScrollAmount=0" onmouseout="iScrollAmount=1"> 
　　轻轻的我走了，正如我轻轻的来；<br/> 
　　我轻轻的招手，作别西天的云彩。<br/> 
　　那河畔的金柳，是夕阳中的新娘；<br/> 
　　波光里的艳影，在我心头荡漾。 <br>
</div> 
<script> 
var oMarquee = document.getElementById("mq"); //滚动对象 
var iLineHeight = 16; //单行高度，像素 
var iLineCount = 4; //实际行数 
var iScrollAmount = 1; //每次滚动高度，像素 
function run() { 
oMarquee.scrollTop += iScrollAmount; 
if ( oMarquee.scrollTop == iLineCount * iLineHeight ) 
oMarquee.scrollTop = 0; 
if ( oMarquee.scrollTop % iLineHeight == 0 ) { 
window.setTimeout( "run()", 2000 ); 
} else { 
window.setTimeout( "run()", 50 ); 
} 
} 
oMarquee.innerHTML += oMarquee.innerHTML; 
window.setTimeout( "run()", 2000 ); 
</script>