感谢梅花老大,分享个跨browser的交换位置节点的js!

Question

不好意思,贴错拉,应该是:
<div id="mContainer" name="mContainer">
<div id="a0" name="nContainer">nContainer[0]<input type="button" value="上" onclick="doSwapNode(0,this.parentNode);"/><input type="button" value="下" onclick="doSwapNode(1,this.parentNode);"/></div><div id="a1" name="nContainer">nContainer[1]<input type="button" value="上" onclick="doSwapNode(0,this.parentNode);"/><input type="button" value="下" onclick="doSwapNode(1,this.parentNode);"/></div><div id="a2" name="nContainer">nContainer[2]<input type="button" value="上" onclick="doSwapNode(0,this.parentNode);"/><input type="button" value="下" onclick="doSwapNode(1,this.parentNode);"/></div><div id="a3" name="nContainer">nContainer[3]<input type="button" value="上" onclick="doSwapNode(0,this.parentNode);"/><input type="button" value="下" onclick="doSwapNode(1,this.parentNode);"/></div><div id="a4" name="nContainer">nContainer[4]<input type="button" value="上" onclick="doSwapNode(0,this.parentNode);"/><input type="button" value="下" onclick="doSwapNode(1,this.parentNode);"/></div><div id="a5" name="nContainer">nContainer[5]<input type="button" value="上" onclick="doSwapNode(0,this.parentNode);"/><input type="button" value="下" onclick="doSwapNode(1,this.parentNode);"/></div>
</div><SCRIPT LANGUAGE="JavaScript">
var activeNode = -1;
var allObj=new Array();
var topObj;
var objLength;
function doSwapNode(direction,obj)
{
   activeNode = findNode(obj);
   if(activeNode==-1)return;
   mDIV = allObj[activeNode].cloneNode(true);
   if(!direction)
   {
      if(activeNode-1<0)return;
  topObj.insertBefore(mDIV,allObj[activeNode-1]);
      topObj.removeChild(allObj[activeNode]);
   }
   else
   {
      if(activeNode+1==objLength)return;
  if(activeNode+2==objLength)
  {
     if(document.all)
 {
    topObj.insertBefore(mDIV);
topObj.removeChild(allObj[activeNode]);
 }
 else
 {
    topObj.insertBefore(mDIV,allObj[objLength+2]);
topObj.removeChild(allObj[activeNode]);
 }
  }
  else
  {
  topObj.insertBefore(mDIV,allObj[activeNode+2]);
  topObj.removeChild(allObj[activeNode]);
  }
   }
}function findNode(obj){
   topObj = document.getElementById("mContainer");
   var allObj1 = topObj.getElementsByTagName("DIV");
   //objLength=allObj.length;   for(var i=0; i<allObj1.length; i++)
   {
     if(isNaN(parseInt(allObj1[i].id)))
 {
    allObj[i]=allObj1[i];
 }   
   }
   objLength = allObj.length;
   for(var i=0;i<objLength;i++)
   {
      if(allObj[i] == obj)  {      return i;
         break;
        
     }
 
   }}</SCRIPT>

Answer 1

DHTML本身就提供了一个交换节点的功能
object.swapNode(targetNode);
不需要自己写的。

Answer 2

关于日期的常见操作
http://community.csdn.net//Expert/TopicView2.asp?id=4360247&datebasetype=now
js FAQ贴
http://community.csdn.net//Expert/TopicView2.asp?id=4356360&datebasetype=now
DHTML手册,js手册,dom手册下载,梅花雪的树和日期控件
梅雪香的日期控件.
http://community.csdn.net//Expert/TopicView2.asp?id=4356325&datebasetype=now

Answer 3

梅香雪,你说的swapNode好象是ie独有的啊
firefox可以吗
/?