请教：Javascript模拟FORM以POST方式提交表单数据

Question

function AddDataPost(sUserId,sUserName) 
{
var obj = new ActiveXObject("Microsoft.XMLHTTP"); sUserId = escape(sUserId);
sUserName = escape(sUserName); 
var userInfo = "userid="+sUserId+"&username="+sUserName; 
obj.open("POST","getData.asp",false); 
obj.setRequestHeader("Content-Type","application/x-www-form-urlencoded") 
obj.send(userInfo); 
return unescape(obj.responseText);
}
取值的时候必须用unescape()函数<% @Language="JavaScript" %>
<%
var userId = unescape(Request.Form("userid")); 
var userName = unescape(Request.Form("username")); 
Response.write("ID: "+ userId +"; Name: "+ userName);
%>

Answer 1

document.write('<form name=myForm>');
var myForm=document.forms['myForm'];
myForm.action='';
myForm.method='POST';
myForm.submit();

Answer 2

谢谢 二位指教最终采用了 swfclyb 的方法（实现比较简单）再次感谢二位。谢谢！