当鼠标放在INPUT上面，显示INPUT上面的VALUE 谢谢

<input type="checkbox" value="10" onMouseOver="this.title=this.value">

解决方案 »

  1.   

    <HTML>
    <HEAD>
    <TITLE> New Document </TITLE>
    <META Http-Equiv="Content-Type" Content="text/html; charset=gb2312">
    <SCRIPT LANGUAGE="JavaScript">
    <!--
    function showtitle(vvv)
    {
    var strid= vvv.id ;
    var ctl = document.all[strid];
    ctl.title= ctl.value ;
    }
    //-->
    </SCRIPT>
    </HEAD><BODY>
    <INPUT TYPE="text" NAME="t1" id ="t1" onmousemove=showtitle(this) value="1">
    </BODY>
    </HTML>
      

  2.   

    <input type="text" id="test" value="test" size="5" onMouseMove="this.title=this.value">
      

  3.   

    <input type="text" name="t1" id ="t1" onmousemove="this.title=this.value" value="1">
      

  4.   

    <HTML>
    <BODY>
    title有时不是很灵敏 用层效果比较好一些<br>
    <input name=dd value=text1 onmouseover=show(this.value) onmouseout=hid()>
    <br>
    <input name=dd value=text2 onmouseover=show(this.value) onmouseout=hid()>
    <div id=mydiv  style="position:absolute;visibility:hidden;width:100px;;height:30px;background-color:seashell"></div>
    </BODY>
    </HTML>
    <script>
       function show(value)
          {
                  mydiv.innerHTML='<a style="border:1px solid red;width:100px;height:30px;TEXT-ALIGN:left">'+value+'</a>'

    mydiv.style.pixelLeft=event.clientX+document.body.scrollLeft
    mydiv.style.pixelTop=event.clientY+document.body.scrollTop+10
    mydiv.style.visibility="visible"
          }
        function hid()
          {mydiv.style.visibility="hidden"}
    </script>
      

  5.   

    <input type="submit" name="Submit" value="提交" title="提交">