怎么简化这个呢

Question

 $(".list-type").css("display")=="none" ?$(".list-type").css("display","block"):$(".list-type").css("display","none");    $(".type-shop-list").css("display")=="none" ?$(".type-shop-list").css("display","block"):$(".type-shop-list").css("display","none"); 如果显示的就隐藏，如果隐藏的就显示

Answer 1

$(".list-type,.type-shop-list").toggle();