求一个正则表达式（或者更好的方法推荐）

Question

正则表达式

Answer 1

我是意思是：比如有一个账号 111333（六位数 匹配了 AAABBB） 所以要过滤点   如 123456 就不用过滤掉

Answer 2

/(\d)(?=\1(\d)(?=\2(\d)(?=\3)))/            //AABBCC
/(\d)(?=\1\1(\d)(?=\2\2))/                //AAABBB
/(\d{2})(?=\1\1)/                     //ABABAB
/(\d{3})(?=\1)/                      //ABCABC
/(\d)(?=\1(\d)(?=\2(\d)(?=\3)))|(\d)(?=\4\4(\d)(?=\5\5))|(\d{2})(?=\6\6)|(\d{3})(?=\7)/           //以上四种情况

Answer 3

//号码位数
for (long i = 100000; i < 10000000; i++) {
String code = String.valueOf(i);
regx = "([\\d])\\1{5,}"; // 6A+ //处理顶级 AAAAAA++
Pattern pattern6AA = Pattern.compile(regx);
Matcher matcher6AA = pattern6AA.matcher(code); regx = "^.*(.)\\1{5}.*$"; // 6A //处理 6A
Pattern pattern6A = Pattern.compile(regx);
Matcher matcher6A = pattern6A.matcher(code);
// 1.处理5A++
regx = "^.*(.)\\1{4}.*$"; // 5A
Pattern pattern5A = Pattern.compile(regx);
Matcher matcher5A = pattern5A.matcher(code);
regx = "^.*(.)\\1{3}.*$"; // 4A
Pattern pattern4A = Pattern.compile(regx);
Matcher matcher4A = pattern4A.matcher(code);
regx = "^.*(.)\\1{2}.*$"; // 3A
Pattern pattern3A = Pattern.compile(regx);
Matcher matcher3A = pattern3A.matcher(code); regx = "^.*(\\d)(?=\\1{2}(\\d)(?=\\2{2})).*$"; // AAABBB 也会生成 4A 问题
Pattern patternAAABBB = Pattern.compile(regx);
Matcher matcherAAABBB = patternAAABBB.matcher(code); regx = "^.*(\\d)(?=\\1(\\d)(?=\\2(\\d)(?=\\3))).*$"; // AABBCC
// 也会生成4A
Pattern patternAABBCC = Pattern.compile(regx);
Matcher AABBCC = patternAABBCC.matcher(code); regx = "^.*(\\d)(?=\\1{1}(\\d)(?=\\2{1})).*$"; // AABB
Pattern patternAABB = Pattern.compile(regx);
Matcher AABB = patternAABB.matcher(code); regx = "^.*(\\d{2})(?=\\1{2}).*$"; // ABABAB
Pattern patternABABAB = Pattern.compile(regx);
Matcher matcherABABAB = patternABABAB.matcher(code); regx = "^.*(\\d{2})(?=\\1).*$"; // ABAB
Pattern patternABAB = Pattern.compile(regx);
Matcher ABAB = patternABAB.matcher(code); regx = "^.*(\\d{3})(?=\\1).*$"; // ABCABC
Pattern patternABCABC = Pattern.compile(regx);
Matcher ABCABC = patternABCABC.matcher(code);
}