比较麻烦的json格式的解析

Question

jsonajaxjquery

Answer 1

你吧json字符串帖出来 ，感觉没多复杂，

Answer 2

var json = [{"首页信息":[{"functionid":"distributor_shouye_jiben","functionname":"基本信息","id":21,"level":3,"num":1,"parentfunctionid":"distributor_shouye","status":1,"usertype":1},{"functionid":"distributor_shouye_fapiaoshenqing","functionname":"发票申请","id":21,"level":3,"num":1,"parentfunctionid":"distributor_shouye","status":1,"usertype":1}]}];
    alert(json[0]["首页信息"][0]['functionname']);
    alert(json[0]["首页信息"][1]['functionname']);

Answer 3

json[0]["首页信息"][0]['functionname'] //基本信息
json[0]["首页信息"][1]['functionname'] //发票申请

Answer 4

json[0]["首页信息"][0]['functionname'] //基本信息
json[0]["首页信息"][1]['functionname'] //发票申请
是写单个的，我循环输出map的key 和 map的value~

Answer 5

那就循环处理呗
能不能给我 举例一个循环处理 map<string ,list<object>>解析的例子啊？

Answer 6

var json = '[{"首页信息":[{"functionid":"distributor_shouye_jiben","functionname":"基本信息","id":21,"level":3,"num":1,"parentfunctionid":"distributor_shouye","status":1,"usertype":1},{"functionid":"distributor_shouye_fapiaoshenqing","functionname":"发票申请","id":21,"level":3,"num":1,"parentfunctionid":"distributor_shouye","status":1,"usertype":1}]},{"底部信息":[{"functionid":"distributor_shouye_jiben","functionname":"底部信息","id":21,"level":3,"num":1,"parentfunctionid":"distributor_shouye","status":1,"usertype":1},{"functionid":"distributor_shouye_fapiaoshenqing","functionname":"支票申请","id":21,"level":3,"num":1,"parentfunctionid":"distributor_shouye","status":1,"usertype":1}]}]';
    json = $.parseJSON(json);
    for (var i in json) {
      
      for (var j in json[i]) {
        for (var l = 0; l < json[i][j].length; l++) {
          if(json[i][j][l]['functionname'] != 'undefind'){
            console.log(json[i][j][l]['functionname']);
          }else{
            break;
          }
          
        }
        
      }
    }