jquery jqgrid setRowData 方法求解

Question

jqgrid jquery

Answer 1

var cm=[
   {name:'name',label:'Name', width:150,editable: true},
   {name:'id',width:50, sorttype:"int", editable: true,formatter:strongFmatter},
   {name:'email',label:'Email', width:150,editable: true,formatter:'email'},
   {name:'stock',label:'Stock', width:60, align:"center", editable: true,formatter:'checkbox',edittype:"checkbox"},
   {name:'item.price',label:'Price', width:100, align:"right", editable: true,formatter:'currency'},
   {name:'item.weight',label:'Weight',width:60, align:"right", editable: true,formatter:'number'},
   {name:'ship',label:'Ship Via',width:90, editable: true,formatter:'select', edittype:"select",editoptions: value:"2:FedEx;1:InTime;3:TNT;4:ARK;5:ARAMEX"}},      
   {name:'note',label:'Notes', width:100, sortable:false,editable: true,edittype:"textarea", editoptions:{rows:"2",cols:"20"}}      
 ];///cm[cm.length]={label:'xxxxx',width:100,editable: true}
cm[cm.length].name=item.key//........其他代码
colModel:cm

Answer 2

colModel: [
         
              {name:"darea.d_area_name",index:"darea.d_area_name",label:"宿舍区域"},//(1)
              {name:"roomusage.r_u_name",index:"roomusage.r_u_name",label:"房间用途"},//(2)
              {name:"building_no",index:"building_no",label:"楼号"},
],var dataRow = {  
                 d_area_name:darea,//这行代码运行后没反应，但是darea.d_area_name没用按官方文档应该用(同1处)，darea.d_area_name
                 building_no:rowData.building_no,//这行代码运行正确
                 colModel:room//这行代码运行后没反应，但是darea.d_area_name没用按官方文档应该用(同2处)，roomusage.r_u_name 改成roomusage.r_u_name没法运行。
                    };  
                $("#gridTable").jqGrid("setRowData", selectedRowId, dataRow);  

Answer 3

jqgrid不能设置为子键吧。。“darea.d_area_name”作为一个整体的键名称了，要改成这样
    var dataRow = {
        "darea.d_area_name": darea, 
        building_no: rowData.building_no, 
        "roomusage.r_u_name": room
    };