<tr onmouseover="this.children[0].children[0].src='aaa.gif';">

解决方案 »

  1.   

    <tr onMouseOver="pic.src='2.jpg'" onMouseOut="pic.src='1.jpg'">
        <td><img src="1.jpg" id="pic"></td>
      </tr>
      

  2.   

    <script language=javascript>
    function changeimg()
    {
    document.getElementById("aa").innerHTML = "<img src='http://community.csdn.net/ADV/Images/banner100x300.GIF'>"
    }
    </script>
    <table>
    <tr onmouseover="changeimg();">
    <td id="aa"><img src="http://community.csdn.net/images/CSDN_logo.GIF"></td>
    <td>look</td>
    </tr>
    </table>
      

  3.   

    <tr onmouseover="this.getElementsByTagName('img')[0].src = '图片路径'">
    <td><img src="images/red.gif" width="3" height="3"></td>
    <td>asdfasdf</td>
    </tr>
      

  4.   

    <tr onmouseover="this.children[0].children[0].src='aaa.gif';">哈,这个新鲜。。
      

  5.   

    第一个td
    <tr onmouseover="this.children[0].getElementsByTagName('img')[0].src = '图片路径'">
    <td><img src="images/red.gif" width="3" height="3"></td>
    <td>asdfasdf</td>
    </tr>