怎么计算两个时间之间的工作日（去掉周六日）

Question

<% 
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'''    函数名:WorkingDay(day_star,day_end)                     '''
'''    功  能:计算一个时间段里面的工作日(每周去掉周六,周日)    '''
'''    参  数:day_star:时间段的起始时间,时间格式:yyyy-mm-dd    '''
'''           day_end:时间段的结束时间,时间格式:yyyy-mm-dd     '''
'''    返回值:返回工作日的值                                   '''
'''    作  者:Eyun(艺云):http://www.eyun.org
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function WorkingDay(day_star,day_end)
dim weeks,week_star,week_end
weeks=datediff("ww",day_star,day_end,2) '把星期一作为一个星期
'的开始,判断有几个星期
week_end=weekday(day_end,2) '判断开始那天为星期星期几
if week_end=7 or week_end=6 then '当星期六,日时调整
week_end=5
end if
week_temp=weekday(day_star,2) '判断结束那天为星期星期几
if week_temp=7 then '当星期六,日时调整
week_temp=6
end if
week_star=6-week_temp
WorkingDay=(weeks-1)*5+week_star+week_end
end function
response.Write(WorkingDay("2005-04-29","2005-06-01"))
%>

Answer 1

<script language=javascript>var d=new Date("2005/02/02");
var d2=new Date("2005/03/19");
var t;
t=weekCount(d,d2);
document.write(t);
///////////////////////////
function weekCount(dStart,dEnd)
{
    var iSatCount = 0;
    var iSunCount = 0;
var sumDay = 0;
    do{
        if(dStart.getDay()==6 || dStart.getDay()==0)
  iSatCount++;
 else
  sumDay++;
        dStart.setDate(dStart.getDate()+1);
    }while(dStart.getTime()<=dEnd.getTime())
    return sumDay;
}
</script>

Answer 2

<script language=javascript>
var ma=new Date("2005/1/1")
var ma2=new Date("2006/1/1")
var num=0
while(ma.getTime()<ma2.getTime())
{
if(ma.getDay()!=0 && ma.getDay()!=6)
{
num++
}
ma.setDate(ma.getDate()+1)
}
document.write(num)
</script>

Answer 3

看错了,写了个vbscript的
用循环如果时间长的话会不会开销太大啊
看看这个行不行:
<script>
//''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
//''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
//''''   函数名:WorkingDay(day_star,day_end)                              ''''
//''''   功  能:计算一个时间段里面的工作日(每周去掉周六,周日)             ''''
//''''   参  数:day_star:时间段的起始时间,时间格式:yyyy/mm/dd             ''''
//''''          day_end:时间段的结束时间,时间格式:yyyy/mm/dd              ''''
//''''   返回值:返回工作日的值                                            ''''
//''''   作  者:Eyun(艺云):http://www.eyun.org                            ''''
//''''   时  间:2005-06-14                                                ''''
//''''   环  境:javascript                                                ''''
//''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
//''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
function WorkingDay(day_star,day_end){
var week_end,week_star,days,weeks,remain,work_days;
day_star=new Date(day_star);
day_end=new Date(day_end);
days=(day_end.getTime()-day_star.getTime())/(24*60*60*1000)+1;
//alert(days);
//alert(days/7);
weeks=Math.floor(days/7);
remain=days%7;
//alert("rmain:"+remain);
week_star=day_star.getDay();
week_end=day_end.getDay();
//alert("week:"+weeks);
if(week_end==0||week_end==6)week_end=5;
if(week_star==0||week_star==6)week_star=1;
//alert("star:"+week_star);
//alert("end:"+week_end);
if(week_end<week_star)week_end+=5;
if(week_end==5&&week_star==1)week_end=week_star-1;
remain=week_end-week_star+1;
work_days=weeks*5+remain;
alert(work_days);
}
</script><a href="#" onClick="WorkingDay('2004/6/12','2005/6/25')">查看函数运行结果</a>