高分求JAVASCRIPT中怎么得到昨天的年月日日期

Question

var d = new Date();
d.setTime(d.getTime() - (24*60*60*1000));
alert(d.getDate());

Answer 1

var d=new Date();
var time=d.getTime();
time-=24*60*60*1000;
d.setTime(time);

Answer 2

var d = new Date();
d.setTime(d.getTime() - (24*60*60*1000));
alert(d.getDate());

Answer 3

直接在构造器中把日期减1，遇到负数的时候，会自动回退
  var d = new Date(2005,5,1);
  alert(d)
  var dz=new Date(d.getYear(),d.getMonth(),d.getDate()-1);
  alert(dz)

Answer 4

<script>
var d = new Date();
d.setTime(d.setDate(d.getDate()-1));alert(d.getYear());
alert(d.getMonth()+1);
alert(d.getDate());
</script>不会发生楼主想象的那种问题! 
楼主可以测试@_@

Answer 5

修改一下:<script>
var d = new Date();
d.setDate(d.getDate()-31);alert(d.getYear());
alert(d.getMonth()+1);
alert(d.getDate());</script>

Answer 6

晕, 又错了<script>
var d = new Date();
d.setDate(d.getDate()-1);alert(d.getYear());
alert(d.getMonth()+1);
alert(d.getDate());
</script>

Answer 7

<SCRIPT LANGUAGE="JavaScript">
<!--
var d = new Date();
d.setDate(d.getDate()-1);
alert(d.toString());//-->
</SCRIPT>

Answer 8

日期减去天数等于第二个日期
<script language=Javascript>
function cc(dd,dadd)
{
//可以加上错误处理
var a = new Date(dd)
a = a.valueOf()
a = a - dadd * 24 * 60 * 60 * 1000
a = new Date(a)
alert(a.getFullYear() + "年" + (a.getMonth() + 1) + "月" + a.getDate() + "日")
}
cc("12/23/2002",2)
</script>

Answer 9

var dt = new Date();
dt.setDate(dt.getDate()-1);
return dt