求每隔4分钟,跳出提示窗口代码,很简单的一时想不起来了

Question

var f = function(){window.open("tip.htm",null,"width=200px,height=200px,menubar=no,location=no,toolbar=no,scrollbars=no");
setInterval(f, 60*1000*4);

Answer 1

<script language="JavaScript">
function promptwin()
{ if (!window['winhdl'] || window['winhdl'].closed)
{
window['winhdl'] = window.open();
window['winhdl'].document.open('html/txt');
window['winhdl'].document.write('<font color=red>Warning</font>');
window['winhdl'].document.close();
}
}window.setInterval("promptwin()",4*60*1000);
</script>

Answer 2

用setInterval这个函数就可以实现

Answer 3

用这个也可以实现<script>SetTimeout("window.location.href='网页名'，40000)</script>

Answer 4

不好意思写错了<script>settimeout("alert('')“，40000）</script>