<SCRIPT LANGUAGE="JavaScript">
<!--
var result = new ActiveXObject("Msxml2.DOMDocument");
var xml ="<root><item id=\"1\"><num1>11</num1><num2>12</num2></item><item id=\"2\"><num1>21</num1><num2>22</num2></item></root>";
var a = result.loadXML(xml); var root = result.documentElement; var s = result.selectNodes("//item"); alert(s[0].childNodes[0].text);//-->
</SCRIPT>你的xml格式都没正确,id="1" root没封闭
<!--
var result = new ActiveXObject("Msxml2.DOMDocument");
var xml ="<root><item id=\"1\"><num1>11</num1><num2>12</num2></item><item id=\"2\"><num1>21</num1><num2>22</num2></item></root>";
var a = result.loadXML(xml); var root = result.documentElement; var s = result.selectNodes("//item"); alert(s[0].childNodes[0].text);//-->
</SCRIPT>你的xml格式都没正确,id="1" root没封闭
root.childNodes[0].childNodes[1]得到l2
root.childNodes[1].childNodes[0]得到21
root.childNodes[2].childNodes[1]得到22
不过万一我的顺序有错乱
那就会得到不正确的数据发现还有更好的
function getNodeValue(root,NodeName) {
try{
var node = root.selectSingleNode(NodeName);
return node.text;
}catch(e){
return "";
}
}function getNodeAttributes(Nodes)
{
var text="";
for (var i=0;i<Nodes.length;i++)
{
var node = Nodes[i];
var id=node.getAttribute("id");
var num1=getNodeValue(node,"num1");
var num2=getNodeValue(node,"num2");
alert("id=" + id);
alert("num1=" + num1);
alert("num2=" + num2);
}
return text;
}
for(var i=0; i<nodes.length; i++) {
var xNode = nodes.item(i);
var nums = xNode.childNodes;
for(var j=0; j<nums.length; j++) {
var item = nums.item(j);
alert(item.text);
}
}