高分送出，用JS格式化日期？

n_year=Request("year")
n_month=Request("month")
n_date=Request("date")rs("date-date")=n_year&"-"&n_month&"-"&n_date

解决方案 »

  1.   

    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=gb2312">
    <script language="JavaScript">
    <!--
    function showResult(){
    var date=new Date(dltYear.value+"/"+dltMonth.value+"/"+dltDay.value);
    var year=date.getFullYear();
    var month=returnMonth(date.getMonth());
    var day=date.getDate();
    day=day<10?"0"+day:day;
    var strDate=day+"-"+month+"-"+year;
    alert(strDate);
    }
    function returnMonth(num){
    var str="";
    switch(num){
    case 0: str="JAN"; break;
    case 1: str="FEB"; break;
    case 2: str="MAR"; break;
    case 3: str="APR"; break;
    case 4: str="MAY"; break;
    case 5: str="JUN"; break;
    case 6: str="JUL"; break;
    case 7: str="AUG"; break;
    case 8: str="SEP"; break;
    case 9: str="OCT"; break;
    case 10: str="DEC"; break;
    case 11: str="NOV"; break;
    }
    return str;
    }
    //-->
    </script>
    </head>
    <body>
    <select name="dltYear">
    <option value="2005">2005</option>
    </select>
    <select name="dltMonth">
    <option value="1">1</option>
    </select>
    <select name="dltDay">
    <option value="6">6</option>
    </select>
    <input type="button" onClick="showResult();" value="查看结果">
    </body>
    </html>
      

  2.   

    function returnMonth(num){
    var arr=new Array("JAN","FEB","MAR","APR","MAY","JUN","JUL","AUG","SEP","OCT","DEC","NOV");
    return arr[num];
    }
    把这个函数替换一下