var a=new String("壹","二",....
var c=new String("元","百","任"....
var d=new String("角","分");
如果一个数b在点的右边 e 位,把这个数b变为 a[b]并在其后加 d[e]
如果一个数b在点的左边 e 位,把这个数b变为 a[b]并在其后加 c[e]
var c=new String("元","百","任"....
var d=new String("角","分");
如果一个数b在点的右边 e 位,把这个数b变为 a[b]并在其后加 d[e]
如果一个数b在点的左边 e 位,把这个数b变为 a[b]并在其后加 c[e]
function Chinese(num) //
{
if(!/^\d*(\.\d*)?$/.test(num)){alert("Number is wrong!"); return "Number is wrong!";} var AA = new Array("零","壹","贰","叁","肆","伍","陆","柒","捌","玖");
var BB = new Array("圆","拾","佰","仟","萬","億","点","");
var a = (""+ num).replace(/(^0*)/g, "").split("."), k = 0, re = ""; for(var i=a[0].length-1; i>=0; i--)
{
switch(k)
{
case 0 : re = BB[7] + re; break;
case 4 : if(!new RegExp("0{4}\\d{"+ (a[0].length-i-1) +"}$").test(a[0]))
re = BB[4] + re; break;
case 8 : re = BB[5] + re; BB[7] = BB[5]; k = 0; break;
}
if(k%4 == 2 && a[0].charAt(i+2) != 0 && a[0].charAt(i+1) == 0) re = AA[0] + re;
if(a[0].charAt(i) != 0) re = AA[a[0].charAt(i)] + BB[k%4] + re; k++;
} if(a.length>1) //加上小数部分(如果有小数部分)
{
re += BB[6];
for(var i=0; i<a[1].length; i++) re += AA[a[1].charAt(i)];
}
return re;
}