关于用javascript做一个弹出登陆窗口的问题

Question

<SCRIPT LANGUAGE="JavaScript">
var winWidth=340;
var winHeight=210;
var top = (screen.availHeight/2)-(winHeight/2);
var left = (screen.availWidth/2)-(winWidth/2);
window.open("22.htm","","toolbar=no,menubar=no,scrollbars=no,resizable=no,location=no,status=no,width="+winWidth+",height="+winHeight+",top="+top+",left="+left);
window.close;
</SCRIPT>

Answer 1

思路：
在主窗口中根据session来判断，没登陆则打开一个登陆窗口，并在子窗口中弹出的时候把父窗口关闭，登陆成功则重新开一个新窗口显示主窗口，同样把登陆窗口关闭<script language="javascript"> 
<!--
    var hWnd=window.open("url.jsp","登录界面","width=170,height=115,toolbar=no,status=no,menubar=no,scrollbar=no,left=300,top=220");
    hWnd.focus();
-->
</script> 

Answer 2

window.showModalDialog( "login.html", "", "dialogWidth:197px; dialogHeight:210px; dialogLeft:600px; dialogTop:100px; status:no; directories:yes;scrollbars:no;Resizable=no; "  );

Answer 3

不應使用window.open()來做,應該使用showModalDialog()來做!
window.showModalDialog( "login.html", "", "dialogWidth:197px; dialogHeight:210px; dialogLeft:600px; dialogTop:100px; status:no; directories:yes;scrollbars:no;Resizable=no; "  );