100求教一个紧急问题

Question

<script>
function a(s){return s.replace(/-(\d)(?=\D|$)/g,"-0$1");}
alert(a("2003-1-6"));
alert(a("2003-10-6"));
alert(a("2003-1-16"));
</script>

Answer 1

<script>
function MakeArray(n) {
this.length = n
return this
}
function customDateString(oneDate) { var theMonth = oneDate.getMonth() + 1;
var theYear = oneDate.getYear(); 
if (theMonth<10){theMonth="0"+theMonth}
var theDay = oneDate.getDate()
if (theDay<10){theDay="0"+theDay}
if  (theYear < 1900) { theYear = theYear + 1900}; var today = theYear + "-" + theMonth + "-" + theDay; return today;
}document.write(customDateString(new Date()))</script>

Answer 2

呵呵,还是 fason(阿信) 的简练.

Answer 3

myblessu(寒飞) :
谢谢你，但是
oneDate.getMonth() 会出错。因为
输入oneDate是2003-7-7系统不认为是日期fason(阿信)：您的方法对了。谢谢

Answer 4

扩展一下
function a(s){return s.replace(/([-: ])(\d)(?=\D|$)/g,"$10$2");}
alert(a("2003-1-6 12:1:1"));
alert(a("2003-10-6 2:1:5"));
alert(a("2003-1-16 22:7:5"));

Answer 5

你好，在function a(s){return s.replace(/-(\d)(?=\D|$)/g,"-0$1");}中在ie6可以正常运行，但是我们的生产环境都是ie5请问这个函数在ie5中会出错，请问用什么别的方法也实现这个功能呢？

Answer 6

<script>
function a(v) {
  v += "."
  re = /-(\d[^\d])/g;
  while(re.test(v))
    v = v.replace(re,"-0$1");
  return v.substr(0,v.length-1);
}
alert(a("2003-1-1"));
alert(a("2003-11-1"));
alert(a("2003-1-11"));
</script>

Answer 7

<script>
function a(v) {
  return v.replace(/\b(\d)\b/g,'0$1')
}
alert(a("2003-1-1"));
alert(a("2003-11-1 12:1:1"));
alert(a("2003年1月11日"));
</script>

Answer 8

啊信老大，return s.replace(/-(\d)(?=\D|$)/g,"-0$1");
这句话我看不太懂，什么意思，请指教~~~